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slava [35]
3 years ago
6

Darlene bought a twelve pack of apple juice boxes for $3.84. How much did one apple juice box cost?

Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0

Answer:      

8/25  = 0.32000    

Step-by-step explanation:

Step  1  :

                 96

Simplify   ——

                  25

Equation at the end of step  1  :

  96

 —— ÷ 12

  25

Step  2  :

             96      

Divide  ——  by  12

              25      

Final result :

  8          

 —— = 0.32000

  25          

Processing ends successfully

plz mark me as brainliest :)

Maksim231197 [3]3 years ago
5 0

Answer:

$0.32

Step-by-step explanation:

If twelve apple juice boxes cost $3.84, to find the price of a single juice box, we simply divide.

$3.84 ÷ 12 = $0.32

This means each apple juice box costs thirty-two cents.

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Given P(X) = 0.5, P(Y) = 0.4, and P(Y|X) = 0.3, what are P(X and Y) and P(X or Y)?
scZoUnD [109]

Use the definition of conditional probability to find the "and" probability:

P(Y\mid X)=\dfrac{P(X\cap Y)}{P(X)}\implies P(X\cap Y)=0.3\times0.5=0.15

Use the inclusion/exclusion principle to find the "or" probability:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)=0.5+0.4-0.15=0.75

6 0
3 years ago
WILL MARK BRAINLIEST, PLEASE HAALLPPP TT^TT
mina [271]

Answer:

here have a nice life

Step-by-step explanation:

1 Lecture 15: Rates of change

1.1 Outline

• Rates of change, velocity, acceleration.

• Marginal rates

• Equation of motion for objects falling under constant gravity

• Interpreting position and velocity graphs

1.2 Rates of change

If f(t) is a function depending on time, then we can write down the average rate of

change on an interval [t1, t2],

f(t2) − f(t1)

t2 − t1

.

We have defined the instantaneous rate of change at a time t as the limit

f

0

(t) = limr→t

f(r) − f(t)

r − t

.

This is also called the derivative. Thus, instantaneous rate of change is another name

for the derivative. In applications the name rate of change is more descriptive.

If s(t) gives the position of a particle as it moves along a line, then

v(t) = limk→0

s(t + k) − s(t)

k

gives the instantaneous velocity. If position is measured in meters and time in seconds,

the velocity v is measured in meters/second. We will abbreviate meters by m and

seconds by s so that the units for velocity are m/s.

As a second example, let v(t) be a function which gives the v

4 0
3 years ago
If the area of trapezoid is 100 cm, what is the perimeter of the trapezoid?
alexgriva [62]

Answer:

Step-by-step explanation:

If the area of trapezoid is 100 cm²what is the perimeter of the trapezoid?

Area of a trapezoid = 100cm

= 1/2(a + b) × h = 100cm²

Perimeter of a trapezoid = a + b + h

3 0
3 years ago
Write the equation in standard form. 0.5x = y - 4
Nadusha1986 [10]

Answer:

y = 0.5x + 4, or y = 1/2x + 4 (if you prefer fractions)

Step-by-step explanation:

y = mx + b (slope intercept form / standard form) ; m = 0.5 or 1/2, b = 4.

m = linear coefficient/slope(denoted by <u>a</u> in a 1 degree binomial)

b = constant coefficient / y-intercept (denoted by <u>b</u> in a 1 degree binomial)

to convert this equation into a standard form equation. You need to isolate y and leave the coefficients on the other side.

0.5x = y - 4

0.5x (+4) = y - 4 (+4)

0.5x + 4 = y

y = 0.5x + 4

5 0
3 years ago
Read 2 more answers
help please! the pair of figures to the right are similar. what is the ratio of the perimeters and the ratio of the areas?
jasenka [17]

Answer:

Perimeters = 3 in : 7 in

Areas = 9 in² : 49 in²

Step-by-step explanation:

    <em>If the figures are </em><em>squares</em><em>, and the measurements are the length of that sides (as you have said), then we will do the following. </em>

[The left square]

P = 4a

P = 4(15)

P = 60 in

-

A = a²

A = 15²

A = 225 in²

[The right square]

P = 4a

P = 4(35)

P = 140 in

-

A = a²

A = (35)²

A = 1,225 in²

[Simplifying ratios]

Perimeters = 60 in : 140 in

Perimeters = 6 in : 14 in

Perimeters = 3 in : 7 in

-

Areas = 225 in² : 1,225 in²

Areas = 45 in² : 245 in²

Areas = 9 in² : 49 in²

4 0
3 years ago
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