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3 years ago

B.rotation 180

Mathematics

1 answer:

mina [271]3 years ago

4 0

Answer : A. Reflection over the x-axis

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Brooke is starting a business selling silver necklaces at her local farmers market it will cost her $9,403 to purchase the suppl

neonofarm [45]

Answer:

thats cool but is this a math problem? there is no question to answer here just fyi

Step-by-step explanation:

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3 years ago

I’m really struggling! Please help me!!

Andrew [12]

Answer:

8.0

Step-by-step explanation:

The triangle is a right triangle, so we are able to use trigonometric functions. Relative to the angle of 37°, we have the opposite side which is 6 and the adjacent side which is x. The trig function that uses the opposite and adjacent is tangent(SohCahToa). We can set up the following equation:

$tan(37) = \frac{opposite}{adjacent}$

$tan(37) = \frac{6}{x}$

tan(37) evaluates to about , so we can plug it in and solve for x:

$0.7536 = \frac{6}{x} \\0.7536x = 6\\x = 7.962$

To the nearest tenth, x rounds to 8.0.

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1 year ago

Aproxima a las unidades de mil y obtén los resultados estimados

zhenek [66]

Answer:

Step-by-step explanation:

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2 years ago

There are currently 17 frogs in a (large) pond. The frog population grows exponentially, tripling every 6 days. How long will it

Tema [17]

Answer:

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating $\int\limits^ {} \, dF/F =K\int\limits^ {} \, dt$ ⇒ LnF=Kt+c, $F=ce^{Kt}$ ; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), $F=ce^{K0} = F=c=17; F=17e^{6K} =51$ ⇒ $e^{6K} =51/17; K6=ln\frac{51}{17} ; K=ln\frac{51}{17}/6=0.183$ , so $F=17e^{0,183t}$ , now if F=130, t=? we have:

$130=17e^{0.183t} =e^{0.183t} =130/17; 0.183t=ln(130/17); t=ln(130/17)/0.183 = 11,11$

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3 years ago

7 whole number 2/3 -4 5/6 + 2 3/8

denis-greek [22]

Im not sure ask ur teacher

4 0

1 year ago