for it to be balanced in this case would be " <em>4</em> C6H6 + <em>6</em> CI2 = <em>3</em> C6H5CI + <em>9</em> HCI" therefore it's be a <u>Double Replacement</u>
a. We first calculate the moles of sucrose needed
moles sucrose = 0.250 M * 0.25 L
moles sucrose = 0.0625 mol
The molar mass of sucrose 342.3 g/mol, so the mass of
sucrose needed is:
mass sucrose = 0.0625 mol * 342.3 g/mol
mass sucrose = 21.4 grams
So simply dissolved about 21.4 grams of sucrose in 250 mL
solution.
b. We use the formula:
M1 V1 = M2 V2
1.50 M * V1 = 0.100 M * 0.350 L
V1 = 0.0233 L = 23.3 mL
So simply take 23.3 mL of solution from 1.50 M then dilute
it with water until 350 mL to make 0.100 M.
<span>For addition and subtraction you round to decimal places.
Round the number so that it has the same number of decimal places as the number in your data that has the least number of decimal places.
9 cm + 2.8 cm = 11.8 cm
the 9 has no decimal places so
= 12 cm
(this is rounded to 0 decimal places.)
(It has 2 sig figs) </span>
If you don’t mind can u add the picture?? It helps me answer the question better ;)
B. Moles of solute, liters of solution
