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faust18 [17]
2 years ago
11

The following diene does not undergo Diels Alder reaction because _____. Click on text below: A. it does not have an electron do

nating group B. it does not have an electron withdrawing group C. the bicyclic ring does not function as a diene D. it cannot adopt the s-cis conformation E. the double bonds are not in the same cyclic ring
Chemistry
1 answer:
antoniya [11.8K]2 years ago
5 0
28 because of how the penny flips and the Group A is blue so , The book would be 82 So dicvide 7 to 92 And u get 6
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At 303 K, the volume of a gas is 30.0 ml. At constant pressure, what is the new
zloy xaker [14]

Answer:

V₂ = 28 mL

Explanation:

Given data:

Initial temperature = 303 K

Initial volume = 30.0 mL

Final temperature = 283 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 30.0 mL × 283 K /303 K

V₂ = 8490 mL.K / 303 K

V₂ = 28 mL

3 0
2 years ago
Percent composition?: 85.05 g of Mg combines completely with 112.21 g of S.
hammer [34]

Empirical Formula = C20 H60 HG1 S1 O4 (numbers should be in subscript)

Percent Composition =

MG = 43%

S = 56.8%

5 0
3 years ago
Which of the following is an example of a solution? A. An iron alloy B. Iron metal C. An iron ore D. Iron rust
Ganezh [65]
The one that is an example of a solution is : A. an iron alloy
iron alloy consist of minor component that is distributed within the major component, which is the basic requirement for a solution
4 0
2 years ago
How many moles of Ag will be produced from 46.0 g of Cu, assuming AgNO3 is available in excess?
Xelga [282]

Answer:

1.44 mol

Explanation:

Given data:

Mass of Cu = 46 g

Moles of Ag produced = ?

Solution:

Chemical equation:

Cu + 2AgNO₃      →     2Ag  + Cu(NO₃)₂

Number of moles of Cu:

Number of moles = mass/ molar mass

Number of moles = 46 g/63.546 g/mol

Number of moles = 0.72 mol

Now we will compare the moles of Cu and silver from balance chemical equation:

                 Cu           :               Ag

                  1             :                2

               0.72         :             2×0.72 = 1.44 mol

Thus from 46 g of Cu 1.44 moles of Ag is produced .

4 0
3 years ago
This group of fungi forms spores in a round structure on the end of a hyphae
r-ruslan [8.4K]

Answer:

Is zygote fungi an option??

3 0
2 years ago
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