Answer:
802.11ac
Explanation:
It is a wireless networking standard.It functions only on 5 Ghz only. 802.11ac has three times the bandwidth of 802.11n hence it can handle more number of users.It has multi-link throughput of 1 gigabit per second.It provides high throughput.It is very useful for environments with high user density.
Answer:
The correct answer is: <em>Protection from Workplace Retaliation</em>
Explanation:
Protection from Workplace Retaliation is one of the 20 Whistleblower Laws enforced by OSHA. According to the Protection from Workplace Retaliation (PFWR) law, employers cannot treat employees unfairly in retaliation to employees reporting workplace safety hazards to OSHA. The PFWR states that employers cannot retaliate by: denying employees leave, demoting them, firing them, reducing work hours, or denying them promotions.
In this case, Tina's employer violated the Protection from Workplace Retaliation law by giving her menial and difficult jobs in response to her reporting a safety hazard to OSHA.
Question:
To mitigate the effects of most of the common network threats including disruption, destruction and disaster, companies are beginning to migrate their servers, networking devices and data into professional datacenters. This is called
A) Colocation
B) SAAS
C) Peering
D) Clustering
E) Server Farming
Answer:
The correct answer is A) Colocation
Explanation:
Colocation as already defined is the voluntary relocation of all network facilities to a data centre so as to reduce the risks of disaster, disruption, destruction, intrusion whilst increasing security, flexibility and scalability at a lower cost.
As the world gets more digitized, datacentres are getting more patronage. The sales figures show this.
Cheers!
Answer:
#include <iostream>
#include <cstring>
using namespace std;
bool isAPalindrome(char* palindrome);
int main()
{
char palindrome[30];
bool palindrome_check;
cout << "Please enter an word or phrase.\n";
cin.getline(palindrome, 30);
palindrome_check = isAPalindrome(palindrome);
if (palindrome_check = true)
{
cout << "Input is a palindrome\n";
}
else
{
cout << "Inputis not a palindrome\n;";
}
system("pause");
return 0;
}
bool isAPalindrome(char* palindrome)
{
char* front;
char* rear;
front = palindrome;// starts at the left side of the c string
rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s
while (front <= rear)
{
if (front = rear)
{
front++;
rear--;
}
else
{
return false;
}
}
return true;
}
