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Aleksandr-060686 [28]
4 years ago
13

Simplify 3z + 4z +4 -2 -5z when Z=8

Mathematics
2 answers:
Elis [28]4 years ago
5 0

Answer:

18

Step-by-step explanation:

When z=8

Substitute 8 wherever u see z

3(8)+4(8)+4-2-5(8)

24+32+4-2-40

18

Ber [7]4 years ago
3 0

Answer:

18

Step-by-step explanation:

3z + 4z +4 -2 -5z

Combine like terms

3z + 4z  -5z  +4-2

2z+2

Let z=8

2*8 +2

16+2

18

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Nataly [62]

Answer:

6

Step-by-step explanation:

the answer is correct yep

7 0
3 years ago
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4. A geometric sequence is defined recursively by a(1) = 40 and a(n)= a(n-1)
Anarel [89]

The complete question is:

A geometric sequence is defined recursively by

    a_{(1)}=40\text{ and }a_n=(-1/2)a_{(n-1)}

(a) Write out the first four terms of this sequence.

(b) Is the 9th term of this sequence larger or smaller than 1/10? Show the calculation that you use to determine your answer.

Answer:

  • <u>The 9th term is larger than 1/10.</u>

Explanation:

You are given the first term,    a_(1)=40 , and the recursive formula

   a_{(n)}=(-1/2)a_{(n-1}

Thus, you can find the sequence of terms by multiplying each term by the constant ratio, (-1/2).

<u>(a) First four terms of the sequence</u>

a_{(1)}=40\\ \\ a_{(2)}=40\times (-1/2)=-20\\ \\ a_{(3)}=-20\times (-1/2)=10\\\\ a_{(4)}=10\times (-1/2)=-5

Those are the first four terms.

<u>(b) 9th term</u>

You can write the explicit formula of the sequence as:

a_{(n)}=a_{(1)}\times r^{(n-1)}\\ \\ a_{(n)}=40(-1/2)^{(n-1)}

Thus, for the 9th term, n = 9, and the term is:

a_{(9)}=40\times (-1/2)^{(9-1)}\\ \\ a_{(9)}=40\times(-1/2)^8\\ \\ a_{(9)}=40\times(1/256)=0.1526

Since 1/10 = 0.1, and 0.1 < 0.1526, the 9th term is larger than 1/10.

6 0
3 years ago
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ale4655 [162]

Answer:

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Step-by-step explanation:

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The Smith Family bought 4 adult tickets and 5 student tickets, so they spent 36+30=$66 spent.

The difference between them is 69-66=$3.

So, the difference between how much the two families spent is $3.

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5 * 23 is equal to 115. =)
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What is 15/1/20 as a improper fraction
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