Answer:
48, 54 and 60
Step-by-step explanation:
Let the three multiples be 6x, 6(x+1) and 6(x+2) respectively.
6x+6(x+1)+6(x+2)=162
6x+6x+6+6x+12=162
18x=144
x=8
Therefore, the three multiples are 6(8), 6(8+1) and 6(8+2)
i.e. 48, 54 and 60
Answer:
I think it is ± 2y−2X1 −22y− 2X1−2+4=x2=x
Step-by-step explanation:
hope this helps if not let me know
Answer:
all are congruent via SAS
Step-by-step explanation:
Answer:
Step-by-step explanation:
Step-by-step explanation:
The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.
for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.
The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.
substituting 36 for x and 10 for y in eq 1;
3(36) + 10 = 108 + 10 = 118 total students for Green High School
substituting 36 for x and 10 for y in eq2;
4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school
