Using the Pythagorean theorem:
c = sqrt(8^2 + 7^2)
c = sqrt(64 + 49)
c = sqrt(113)
c = 10.6
Answer:
Step-by-step explanation:
c !!
Hey there! :)
Equation 1) 4x = y - 1
Equation 2) 6x - 2y = -3
We want both equations to match in a sense where both x & y are on the same side of the equal sign. To achieve this, simply subtract y from both sides in equation 1.
This will leave us with : 4x - y = -1
Now, line up the equations with one another.
1) 4x - y = -1
2) 6x - 2y = -3
Now, multiply 2 to ALL of equation 1.
2(4x - y = -1)
Simplify.
8x - 2y = -2 → We'll call this new equation 3. Now, line up equation 3 with equation 2.
6x - 2y = -38x - 2y = -2
Subtract equations from one another.
-2x = -1
Divide both sides by -2.
-2x ÷ -2 = -1 ÷ -2
Simplify.
x = 1/2
Now, plug in 1/2 for x into our first equation.
4x - y = -14(1/2) - y = -1
Simplify.
2 - y = -1
Subtract 2 from both sides.
-y = -1 - 2
Simplify.
-y = -3
Divide both sides by -1.
y = 3
So, our answer is : x = 1/2, y = 3 OR (1/2, 3)
~Hope I helped!~
Are you sure you want ONLY the coefficient of b? If you expand this, you will have b in 3 of 4 terms.
According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:
1
1 2 1
1 3 3 1
1 4 6 4 1
So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
Here, you want (3 + b)^4. Here's what that looks like:
3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]
Which coeff did you want?
Answer:
Missing Number) 55
Property being used) Distributive
Step-by-step explanation:
To find the missing number, just plug in reasonable numbers from the other equation. It is distributive because the 55 is being distributed into everything that is inside the parentheses. If you need more help, comment and I'll be more than glad to assist you! :P
