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ankoles [38]
3 years ago
7

Write 108.92 in expanded form.

Mathematics
2 answers:
Vlada [557]3 years ago
5 0

Answer:

1.0892*10²

Step-by-step explanation:

1.0892*10²

yawa3891 [41]3 years ago
3 0

Answer:

108.92 in expanded form :

1 *100+0*10+8*1+9*\frac{1}{10} +2 *\frac{1}{100} \\\\and \\108.92 = 100+ 0+8+0.9+0.02

* Hopefully this helps:) Mark me the brainliest:)!!!

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Verizon [17]
Her statement is possible, the first rectangle could be equal to the second  because x is unknown so if x was 5in in the first rectangle and - 1 in the second rectangle both problems would look like this 2 in & 5 in and the second one 5in & (2 in =  (-1 +3)).

8 0
3 years ago
How many times of 0.00019% to equal 1%
ra1l [238]

Answer:

5263.15789474

Step by Step:

1 ÷ 0.00019 = 5263.15789474

Checking Answer:

0.00019 x 5263.15789474 = 1

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Hope this Helps! :)

4 0
3 years ago
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What is x. pls help me​
ehidna [41]
The answer might be 40
8 0
3 years ago
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5.8 = x/2.2<br><br> A: 127.6<br> B: 0.37<br> C: 3.7<br> D: 12.76
Nataly [62]
Hi there! To solve this, all we have to do is multiply each side by 2.2 to cancel out the variable and to find the value for it. 5.8 * 2.2 is 12.76. 12.76/2.2 is 5.8. x = 12.76. The answer is D.
3 0
3 years ago
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Find an equation for the plane that contains the line v = (−1, 1, 2) + t(7, 6, 2) and is perpendicular to the plane 8x + 5y − 7z
Nadusha1986 [10]
The required plane &Pi; contains the line 
L: (-1,1,2)+t(7,6,2)
means that &Pi; is perpendicular to the direction vector of the line L, namely
vl=<7,6,2>

It is also required that &Pi; be perpendicular to the plane
&Pi; 1 : 5y-7z+8=0
means that &Pi; is also perpendicular to the normal vector of the given plane, vp=<0,5,-7>.

Thus the normal vector of the required plane, &Pi; can be obtained by the cross product of vl and vp, or vl x vp:
 i  j  k
7 6  2
0 5 -7
=<-42-10, 0+49, 35-0>
=<-52, 49, 35> 
which is the normal vector of &Pi;

Since &Pi; has to contain the line, it must pass through the point (-1,1,2), so the equation of the plane is
&Pi; :  -52(x-(-1))+49(y-1)+35(z-2)=0
=>
&Pi; :  -52x+49y+35z = 171

Check that normal vector of plane is orthogonal to line direction vector
<-52,49,35>.<7,6,2>
=-364+294+70
=0   ok
6 0
4 years ago
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