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3 years ago

Jaime has 5 over 11 spaceof a project completed while Tim has finished 7 over 13 spaceof the same project.

Mathematics

1 answer:

faust18 [17]3 years ago

4 0

Answer:

a. Tim has completed a greater amount of work.

b. Together they have completed $\frac{142}{143}$ part of two projects.

Step-by-step explanation:

Let us assume that the project on which Jaime and Tim are working has x amount of space.

Now, given that Jaime has 5 over 11 space of a project completed while Tim has finished 7 over 13 space of the same project.

Therefore, Jaime has completed $\frac{5x}{11}$ amount of space and Tim has finished $\frac{7x}{13}$ amount of space.

a. Now, (7x) \times 11 > (5x) \times 13

⇒ $\frac{7x}{13} > \frac{5x}{11}$

Therefore, Tim has completed the greater amount of work. (Answer)

b. Together they have completed $(\frac{7x}{13} + \frac{5x}{11}) = \frac{(7 \times 11 + 5 \times 13)}{13 \times 11} x = \frac{142}{143}x$ amount of space out of 2x amount of space. (Answer)

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