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3 years ago

Kyle has a storage box that is 2 ft. long, 3 ft. high, and has a volume of 12 ft.3

Mathematics

2 answers:

Eva8 [605]3 years ago

8 0

Alright, let get started.

Kyle has a storage box having dimensions 2 ft long, 3 ft high and volume 12 cubic feet.

The formula for volume is = $length * width * height$

Suppose the width is w so,

$12 = 2 * 3 * w$

$12 = 6w$

Dividing by 6 in both sides

w = 2 feet

Myla has a storage box that is 4 ft high and 2 feet long and volume 16 cubic feet.

Suppose the width is w hence

$16 = 4 * 2 * w$

$16 = 8 w$

Dividing 8 in both sides

w = 2 feet

Hence the width of Kyle and Myla's boxes, both are 2 feet. : Answer

Hope it will help :)

vladimir1956 [14]3 years ago

3 0

Kyle:( 2 x 3 + 12) + Myla: ( 4 x 3 + 16 )
Kyle:18
Myla:28
The Widths are 46

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4 years ago

After t seconds, the height h(t) of a model rocket launched from the ground into the air is given by the function h(t)=-16t^2+80

kipiarov [429]

Lol, why does this sound like one of my seventh grade algebra teacher's problem. Anyway, back to the problem...

The reason why you don't understand this problem is probably because you don't clearly understand h(t) and t itself, and its meaning in the context.

h(t) shows the actual distance from the ground.

t is the actual time after the launch.

For example, when t = 1, it's one second into the launch. Using the function of h(t) = -16t^2 + 80t, we can find the distance off the ground. Doesn't make sense? Feel free to ask questions in the comments below.

So, the question is asking how long it takes the rocket to reach a height of 96 feet. We are trying to find the TIME, which is known as "t," right?

So, what should we do with the "96"? We should plug this in...

96 = -16t^2 + 80t

What we're doing here is showing that some time after the launch, it got up to 96 feet, and we are representing it with this function and plugging in 96 as h(t). At this point, all we have to do is solve the quadratic.

-16t^2 + 80t = 96

-16t^2 + 80t - 96 = 0

WE HAVE TO NOW SIMPLIFY.

-8t^2 + 40t - 48 = 0

-4t^2 + 20t - 24 = 0

-2t^2 + 10t - 12 = 0

-t^2 + 5t - 6 = 0

t^2 - 5t + 6 = 0

(Sorry i did so many steps i'm so tired and my brain is just garbonzo bean fried)

t^2 - 5t + 6 = 0

TWO NUMBERS WHICH MULTIPLY TO 6 AND ADD TO -5

yaaaaaaaaaaaay

t^2 - 3t - 2t + 6 = 0

t ( t - 3) - 2 ( t - 3 ) = 0

(t - 2) (t - 3) = 0

t = 2, t = 3

So basically, it takes t = 2 because the two answers means that it got up to 96 ft in two seconds and then it was going down at 3 seconds and reached 96 ft. Make sense? Just feel free to ask me anything and give me brainliest lol

***credits to my fabulous 7th grade math teacher, Ms. Lam, for teaching me all of this

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4 years ago

The measures of the interior angles of a quadrilateral are x°, 3xº, 5xº, and 7xº. Find the

djverab [1.8K]

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3 years ago

A group of 8 friends went to lunch and spent a total of $76, which included the food bill and a tip of $16. They decided to spli

storchak [24]

Answer:

Each Person:

-In tips: $2

-Food Bill: $7.50

Step-by-step explanation:

Let's find the tip amount for each person. $16 for the whole group. Each person will give in $2 for the tips, for a total of $16 in tips.

Now that tips are done, we must subtract the amount of tips from the food bill, to see how much each person pays. $76 - $16 = $60.

Divide 60 by 8 to get.. 60/8= 7.5.

With 7.5 as an answer, we can conclude that each person paid $7.50 for the food bill.

I see you need to select solutions, may I see them to help you out? The description is pretty vague..

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2 years ago

1. You are standing on top of a ridge using a clinometer trying to figure out how far your dog has wandered off in

olga_2 [115]

Given:

It is given that the ridge is 360 inches tall.

Assumptions:

Assume you are 170.1 cm tall which equals 67 inches tall, the height from your eye to the floor is $360+67 = 427$ inches.

The distance from your eye level to the bottom of the ridge is 427 inches.

Assume the angle A is 60°.

To find the distance from you to your dog.

Solution:

A right-angled triangle can be formed where the angle is 60°, the distance between you and the dog is the hypotenuse of the triangle and your height from the floor is the adjacent side of the triangle.

Assume the hypotenuse of the triangle measures x inches.

To determine the length of the hypotenuse, we determine the cos of the angle.

$cos \theta = \frac{adjacent side}{hypotenuse} .$

$cos A = \frac{427}{x} , x = \frac{427}{cos60} , cos60=0.5.$

$x=\frac{427}{0.5} = 854.$

So if the ridge is 360 inches tall and you are 67 inches tall and the angle A is 60°, the distance between your dog and you is 854 inches.

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4 years ago