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jek_recluse [69]
3 years ago
11

You are going to an amusement park over Spring Break. The cost of admission to enter the park is $30 and the rides are an additi

onal $6 each. If your parents give you $100 to spend at the amusement park, what is the maximum number of rides you can go on? Write an inequality to show the maximum number of rides you can go on.​
Mathematics
2 answers:
vlabodo [156]3 years ago
6 0

Answer:

30+6x ≤ 100 (inequality)

The maximum amount of rides is 11 rides

Step-by-step explanation:

So first the admission fee is 30

Each ride is 6

So since you can go on any amount of rides, its unknown so (x)

You only have a 100 dollars and you can’t go over but you can go lower

so 30+6x≤100

If you solve it

x≤11

So 11 rides

dem82 [27]3 years ago
6 0

Answer:

30+6x=100

Step-by-step explanation:

100-30=70

6*11= 66

The total number of rides he can go on is 11. He will have a remaining balance of $4.00 which is not enough to pay for another ride.

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Answer:

Length = 12 m, Width = 8 m

Step-by-step explanation:

Let the width of the rectangle is b.

Length, l = 4+b

The perimeter of the rectangle = 40 m

We know that,

Perimeter of rectangle = 2(l+b)

2(4+b+b) = 40

4+2b = 20

Subtract 2 from boths sides,

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b = 8

Width = 8 m

Length = 4+8 = 12 m

Hence, the length and the width of the rectangle is 12 m and 8 m respectively.

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