Given:
To find:
The quadrant of the terminal side of 
and find the value of 
.
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,
Here cos is positive and sine is negative. So, 
must be lies in Quadrant IV.
We know that,
It is only negative because lies in Quadrant IV. So,
After substituting , we get
Therefore, the correct option is B.
The last one is 1 I believe
Answer:
220
Step-by-step explanation:
Now, I'm not sure if 220 is correct, but I'll explain my reasoning.
We know three angles of a triangle add up to 180 degrees.
So, the smaller triangle has 70 degrees and <em>a</em><em> </em>and <em>b</em><em> </em>variables. By virtue, <em>a</em><em> </em>+ <em>b</em><em> </em>+ 70 = 180.
So, <em>a</em><em> </em><em>+</em> <em>b</em><em> </em>= 110.
Likewise, when you look at the whole triangle, 70 degrees is also one of the angles while <em>c</em><em> </em>and <em>d</em><em> </em>are unknown.
So, <em>c</em><em> </em>+ <em>d</em> + 70 = 180.
This means <em>c</em><em> </em>+ <em>d</em><em> </em>= 110.
So, <em>(</em><em>a</em><em> </em>+<em> </em><em>b</em><em> </em>) +<em> </em><em>(</em><em>c</em><em> </em>+<em> </em><em>d</em><em> </em><em>)</em><em> </em><em>=</em><em> </em>
110 + 110 =
220 degrees.
I hope this helps!
Answer:
36 CDs
Step-by-step explanation:
32/2=16
16+20
36 CDs is your answer. Have a nice day!
Answer:
Step-by-step explanation:
Start at 1 1/3
Add the negative number.
1 1/3 + (-5/6)
Adding a negative number means to go left on a number line.
-5/6 is equal to -2/3 plus -1/6.
Move 2/3 to the left.
1 1/3 (Start)
1 (1/3)
2/3 (2/3)
Now, move 1/6th to the left.
2/3 is equal to 4/6
4/6 - 1/6 = 3/6
So, put the point at 3/6 or 1/2.
