The cost of a senior citizen ticket is $15 and the cost of a student ticket is $12.
How did I get this?
We know that 6 citizen tickets and 7 student stickers sold for $174 the first day. And 10 citizen tickets and 14 student tickets sold for $318 the second day.
1. create two equations out of this: C= citizen cost per ticket and S = student cost per ticket.
6C + 7S = $174
10C + 14S = $318
2. Use process of elimination. Multiply the first equation by 2 because we want two variables to cancel out.
-12C - 14S = -$348
10C + 14S = $318
Combine like terms.
-2C = $30
Divide by -2 on both sides. The left side cancels out.
C = $30/-2
C = -$15 (In this case the negative doesn't matter)
C = $15 (cost of senior citizen ticket)
Plug the value of C into any of the two equations so we can get the value of S.
6($15) + 7S = $174
Distribute the 6 into the parenthesis.
$90 + 7S = $174
Subtract both sides by $90 and the left side will cancel out.
7S = $84
Divide both sides by 7.
S = $12
Student ticket: $12
Senior citizen ticket: $15
Answer:
L=10.326cm
P=31.30cm
Step-by-step explanation:
A=55=L*W
L=5+W
A = (5+W)(W) = 55
55=W^2 + 5W
0 = W^2 + 5W - 55
use quadratic formula
W = [-5 (+/-) sqrt(25-4(-55))]/2
W= 5.326 cm or W=-20.65, so W=5.326cm
L=5+5.326
=10.326cm
P=2W+2L
P=2(5.326) + 2(10.326)
=31.30 centimeters
The given product is
We have to use the distributive property
Then, we reduce like terms
<h2>Hence, the answer is A.</h2>
Answer:
13 duh
Step-by-step explanation:
The answer is 13 per game because it is a division problem. So you 4 games is 52. So one game is 13 when you divided it by 4. You can also set it up as a proportion 52/4= x/1. Or, you do 52 divided by 4 to get 13.
