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olganol [36]
3 years ago
13

Round 5370238 to the nearest 100,000

Mathematics
1 answer:
qwelly [4]3 years ago
5 0
5370238 8 gets rounded up so add 1
5370240 4 gets rounded down so add nothing
5370200 2 gets rounded down so add nothing
5370000 0 is nothing
5370000 7 gets rounded up so add 1
5,400,000 is the nearest 100,000
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How many thousands of people live in Boston?
Brilliant_brown [7]
600,000 live in Boston
4 0
4 years ago
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Guven the following absolute value function sketch the graph of yhe function and find the domain and range. F (x) = |x + 3| - 1
lana66690 [7]

Answer:

See below

Step-by-step explanation:

The graph is formed from f(x) = |x|.

f(x) = |x| is shaped like a V with the vertex at  the origin and the slope of each arm = 1.  Then f(x) = |x + 3| will have the same shape but will be moved 3 units to the left so the vertex  is at (-3,0). The - 1  ( to give f(x) = |x + 3| - 1) translates the whole graph 1 unit down so the vertex is at the point (-3, -1).

The domain is All Real x and the range = All real values of f(x)

equal or greater than -1.

4 0
4 years ago
Solve the triangle given that a=19 b=16, c=11.
kirill [66]

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle (a, b, c), but all angles are unknown (A, B, C). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that a = 19, b = 16 and c = 11, then the missing angles are, respectively:

Angle A

a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A (1)

A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)

A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right]

A \approx 87.395^{\circ}

Angle B

b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B (2)

B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)

B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right]

B\approx 57.271^{\circ}

Angle C

C = 180^{\circ}-A-B

C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}

C = 35.334^{\circ}

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

8 0
3 years ago
Can someone please help me with this
REY [17]

Answer:

Need to see question

Step-by-step explanation:

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4 0
2 years ago
A table is 3.5 meters long how many centimeters long is the table
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Maybe 70 iam not sure.
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