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3 years ago

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AlladinOne [14]3 years ago

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Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

Prime factorization of 216 in expanded form

Basile [38]

$216|2\\108|2\\.\ 54|2\\.\ 27|3\\.\ \ 9|3\\.\ \ 3|3\\.\ \ 1|\\\\216=2\times2\times2\times3\times3\times3=\huge\boxed{2^3\times3^3}$

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3 years ago

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Write a word phrase for each algebraic expression 49+m

Oksanka [162]

Sarah had $49 dollars, plus the money her mom had.

3 0

4 years ago

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Solving for (3x + 5) = x + 2

Lemur [1.5K]

Answer:

x=-3/2

Step-by-step explanation:

3x+5=x+2

2x=-3

x=-3/2

3 0

4 years ago

Read 2 more answers

In a group of mherchants, 80% of them purchase goods from Asia, and 25% of them purchase goods from Europe. Which of following s

monitta

Answer:

7. 25% of the merchants who purchase goods from Asia also purchase from Europe.

Step-by-step explanation:

I am going to say that:

A is the percentage of merchants who purchase goods from Asia.

B is the percentage of merchants who purchase goods from Europe.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a merchant purchases goods from Asia but not from Europe and $A \cap B$ is the probability that a merchant purchases goods from both Asia and Europe.

By the same logic, we have that:

$B = b + (A \cap B)$

Which of following statement is individually sufficient to calculate what percent of the merchants in the group purchase goods from Europe but not form Asia?

We already have B.

Knowing $A \cap B$ , that is, the percentage of those who purchase from both Asia and Europe, we can find b.

So the correct answer is:

7. 25% of the merchants who purchase goods from Asia also purchase from Europe.

8 0

4 years ago