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4 years ago

Find the measure of the missing angle.

Mathematics

1 answer:

Nostrana [21]4 years ago

5 0

180 minus 90 equals 90, divided by 2, the answer is 45 degrees

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Please help me and ill mark brainlst and explainn

Harlamova29_29 [7]

Answer:

30yd^2

hope this helps!!:)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

6gal 5 pt +3 gal 3 pt= __gal__pt

vovangra [49]

1 gallon=8 pints
so, 5 pints + 3 pints = 8 pints= 1 gallon
and, 6 gallons + 3 gallons= 9 gallons
Finally, 1 gal+9 gal= 10 gallons
Answer: 10 GALLONS

7 0

4 years ago

Read 2 more answers

Carlos ate at the same restaurant four times. Each time he ordered a salad and left 5$ tip. She spent a total of $54 Right and s

mars1129 [50]

Answer:

4k + 20 = 54 is the required equation. ( k = cost of each salad)

The cost of each salad is $8.5.

Step-by-step explanation:

The total amount paid for bill = $54

The tip left each time $5

Number of times the restaurant visited = 4

Now, let k be the total amount of one salad.

Also, total tip paid in 4 visits = 4 x $5 = 20$

So, now according to the question

4k + $20 = $54

or, 4k = 54 - 20 = 34

⇒ 4k = 34

or, k = 34/4 = 8.5

⇒ k= $8.5

So, the cost of each salad is $8.5.

7 0

3 years ago

What are the x and y intercepts for this equation y=−1/4x+2?<br> (_,_)

Firdavs [7]

Answer:

(8, 0) is the x-intercept

(0, 2) is the y-intercept

Step-by-step explanation:

The y-intercept = 2 since the equation is in slope-intercept form.

The x-intercept occurs when y = 0

So, 0 = -1/4x + 2

0 = -x + 8

x = 8

(8, 0) is the x-intercept

(0, 2) is the y-intercept

3 0

3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago