nuala drives to her grandmas. she drives at 20 mph. the journey takes 50 mins. how long would it take if Nuala drove at 40 mph
1 answer:
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Answer: Here we have a real life multiplication situation for which an estimate make sense:-
Miley has 212 fiction books. Sharon has 3 times fiction books has many as Miley has, how many fiction books Sharon has
Solution :- Number of fiction books Miley has = 212
Number of fiction books Sharon has= 3 times 212
We know that 212 is near to 200 , so round off 212 to 200 (to the nearest hundred)
Thus the product becomes
Therefore, the estimated number of fiction books Sharon has=600
The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8
<h3><u>Solution:</u></h3>Let "f" be the cost of 1 fries
Let "h" be the cost of 1 hamburger
<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>
8 x cost of 1 hamburger + 5 x cost of 1 fries = 24
8h + 5f = 24 -------- eqn 1
<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>
6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60
6h + 2f = 16.60 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Multiply eqn 1 by 2
16h + 10f = 48 ------ eqn 3
Multiply eqn 2 by 5
30h + 10f = 83 -------- eqn 4
<em><u>Subtract eqn 3 from eqn 4</u></em>
30h + 10f = 83
16h + 10f = 48
( - ) ----------------------
14h = 35
<h3>h = 2.5</h3>Substitute h = 2.5 in eqn 1
8(2.5) + 5f = 24
20 + 5f = 24
5f = 4
<h3>f = 0.8</h3>Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8
Answer:
C) 2/3x + 3y = 3
Step-by-step explanation:
The attached graph shows only choice C intersects the desired point.
Essentially, the given graph is irrelevant. What you want to know is which equation has (3/4, 5/6) as a solution.
There are at least a couple of ways you can figure this out:
- try the given point in the equations to see which one works
- examine the features of the given equations to see which might work
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If we consider the second approach, we realize all of the equations have negative y-intercepts except choice C*. For an equation with a negative y-intercept to be the solution, the x-intercept must be less than 3/4. That is not the case for any of choices A, B, or D, leaving only choice C as a viable possibility.
We can check to see if the given point satisfies choice C. Filling in for x and y, we get ...
(2/3)(3/4) + 3(5/6) = 2/4 +5/2 = 3 . . . . . . the point is on this line
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In the attached graph, choice C is the black line.
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* For an equation of the form ax+by=c, the y-intercept is c/b and the x-intercept is c/a. The sign of the quotient can be figured from the signs of a, b, and c without doing any division.
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<em>Comment on intercepts</em>
Considering the signs and values of the x- and y-intercepts can tell you a lot about the solution to a system of equations. They tell you where the line segment between the axes lies, and they can give you a clue as to the location (quadrant) of the intersection point of two lines. Often, the intercepts are all you need to create a useful graph of an equation.
