Step-by-step explanation:
2m=480.6
To get m you gotta divide 480.6 by 2
To make m the subject of the formula you have to make 2 cross over to the other side I. E over the equal sign
I. E 480.6/2=240.3
480700. The different combinations of students that could go on the trip with a total of 25 student, but only 18 may go, is 480700.
The key to solve this problem is using the combination formula 
. This mean the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.
The total of students is n and the only that 18 students may go is r:
Answer:
The minimum would be 4,500, and the maximum would be 4,700.
Step-by-step explanation:
If I am not mistaken, you simply need to add or subtract 100 to find the minimum or maximum, as it stated that 4,600 is an estimate that is valid for a range of 100 (up or down).
X = total boats
2/3x are white....so the remaining boats = 1/3x
5/8 of the remaining boats are blue.....5/8 * 1/3 = 5/24x are blue
2/3 + 5/24 = 16/24 + 5/24 = 21/24 are blue and white......so 3/24 are red
3/24x = 6
x = 6 * 24/3
x = 144/3
x = 48 total boats in the marina <==
2/3(48) = 32 white
5/24(48) = 10 blue
3/24(48) = 6 red
Answer:
400
Step-by-step explanation:
20/100 = 80/x
Cross multiply and divide
100 X 80 = 8000 / 20 = 400
