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lora16 [44]
4 years ago
7

There are 3 beakers each of which contains saline solution.

Chemistry
1 answer:
Masja [62]4 years ago
8 0

Answer:

  • <em>Percentage concentration of salt in A</em> = <u>5.3%</u>

Explanation:

Assume all the concentrations are expressed in volumetric terms, i.e 10% = 10 liter salt / 100 liter solution, 20% = 20 liter salt / 100 liter soluton, 0% = 0 liters salt.

1) <u>First transformation</u>: 2 liters are from A to B

<u>Solution A</u>:

  • Concentration: 10 % salt ⇒ 10 liter salt / 100 liter solution

  • Volume of solution: 3 liters

  • Volume of salt: 3 liters × 10 liter / 100 liters = 0.300 liter salt

  • Volume of water: 3 liters - 0.300 liters = 2.700 liters solvent

<u>Solution B</u>:

  • Concentraion: 20%

  • Volume of solution: 2 liter

  • Volume of salt: 2 liter × 0.20 = 0.4 liter salt

  • Volume of water: 2 liter - 0.4  liter = 1.6 liter water

<u>Resultant mixture in beaker B</u>: 2 liters of solution A plus 2 liters of solution B

  • Salt: 2 liter × 0.10 + 2 liter × 0.20 = 0.20 + 0.4 = 0.6 liter salt

                             

  • Water: 2 liter × 0.90 + 2 liter × 0.80 = 3.40 liter water

  • Solution: 2 liter + 2 liter = 4 liter solution

  • Concentration: 0.6 liter salt / 4 liter solution = 0.15 = 15%

2) <u>Second transformation</u>: 1 liter transferred from B to C

  • Salt: <u>1 liter × 0.15</u> + <u>0</u> = 0.15 liter salt

                       ↑              ↑

                  (from B)     ( in C)

  • Solution: 1 liter + 4 liter = 5 liter solution

  • Concentration: 0.15 liter salt / 5 liter solution = 0.03 = 3.0%

3) <u>Third transformation</u>: 2 liters are from C to A.

  • Salt: <u>0.03 liter salt × 2 liter solution</u> + <u>1 liter × 0.10</u> = 0.16 liter salt

                                       ↑                                    ↑

                                (from C)                             (in A)

  • Solution: 2 liter + 1 liter = 3 liter solution

  • % of salt in A = (0.16 liter salt / 3 liter solution) × 100 =5.3 %
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