M= 1 and n = 2
( m+ n = 1 +2 = 3)
rate = K [A] [B]^2
0.2 = K * 3 * 3 ^2
0.2 = K * 3 * 9
K = 0.2 / 27
K = 7.408 * 10 ^ -3 m^-2 s^-1
5000L • 1 mole /22.4L so approximately 223 moles
The energy to vaporize the water at its normal boilng point (100°C) is the vaporization latent heat.
The vaporization latent heat of water is 2257 J/ g (you can find it in a textbook, tables or internet).
So, with 955 kJ you can vaporize this amount of water:
[995 kJ * 1000J/kJ ] / 2557 J /g = 389.13 g
Use the density to convert to volume: D = M / V => V = M / D
V = 389.13 g / 1.00 g / ml = 389.13 ml, which rounded to 3 significant figures is 389 ml
Answer: 389 ml
Answer:
<u>B. 2</u>
Explanation:
A single bond contains <u>2</u> shared electrons.
Given example is that of <u>ethane</u>