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3 years ago

Which expression is equivalent to the fraction below?

Mathematics

1 answer:

iragen [17]3 years ago

6 0

5/8=expression is equivalent to

5 8

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Micheal wants to find the length of a shadow of a tree. He measures the height of a fence post and the length of the shadow it c

Arlecino [84]

Im pretty sure the answer is 92.0 becauese
if you do 10.5x3.5 5x5=25 5x0+2=7 5x1=5 so that will be 57.5 then your going to do 3x5=15 3x0+1=4 3x1=3 that equals 34.5 then your going to add 57.5 +34.5
= 92.0

7 0

3 years ago

Can someone please help me with this question.ASAP

expeople1 [14]

Sorry don't know the answer

8 0

2 years ago

How u write 2.65 in expanded form

SVEN [57.7K]

2 13/20, that should work

7 0

3 years ago

Help! given 2(x-9)=-10 prove x=4 with statements and reasons

Sedbober [7]

Step-by-step explanation:

Proof:

2 ( x - 9) = - 10 when x = 4

2 ( 4 - 9) = -10

8 - 18 = -10

-10 = -10 ..........hence proven

Reasons 

- When you replace X with 4, you can clearly see that the equation is equal to -10.

sorry I couldn't answer accurately, but I hope this helps

8 0

2 years ago

Show all work and reasoning

Natalija [7]

Split up the interval [2, 5] into $n$ equally spaced subintervals, then consider the value of $f(x)$ at the right endpoint of each subinterval.

The length of the interval is $5-2=3$ , so the length of each subinterval would be $\dfrac3n$ . This means the first rectangle's height would be taken to be $x^2$ when $x=2+\dfrac3n$ , so that the height is $\left(2+\dfrac3n\right)^2$ , and its base would have length $\dfrac{3k}n$ . So the area under $x^2$ over the first subinterval is $\left(2+\dfrac3n\right)^2\dfrac3n$ .

Continuing in this fashion, the area under $x^2$ over the $k$ th subinterval is approximated by $\left(2+\dfrac{3k}n\right)^2\dfrac{3k}n$ , and so the Riemann approximation to the definite integral is

$\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n$

and its value is given exactly by taking $n\to\infty$ . So the answer is D (and the value of the integral is exactly 39).

8 0

3 years ago