Answer:
1) f(g(0)) = 0
2) g(f(2)) = 2
3) g(g(0)) = 8
Step-by-step explanation:
Here, the given functions are:
g(x) = 3 x +2 and f(x)= (x-2)/3
1. Now, f(g(x)) = f(3x+2)
Also, f(3x+2) = (3x+2 -2) /3 = x
So, f(g(x)) = x
⇒ f(g(0)) = 0
2. g(f(x)) = g((x-2)/3) = 3((x-2)/3) +2
or, g(f(x)) = x
⇒ g(f(2)) = 3((2)-2/3) +2 = 2
or, g(f(2)) = 2
3. g(g(0)= g( 3 (0) +2) = g(2)
Now, g(2) = 3(2) + 2 = 6 + 2 = 8
or, g(g(0)) = 8
Answer:
b
Step-by-step explanation:
Hey there! I'm happy to help!
Let's convert the decimals to fraction form.
0.5=5/10=1/2
-1/7
-0.2= -2/10= -1/5
1/3
We know that the bigger the number in the denominator, the smaller the fraction is if the numerators are all the same.
First off, we have the negative numbers which are smaller than the other numbers. We have -1/7 and -1/5. We know that the 1/5 is a bigger fraction, but it is negatively bigger, so that is going to be the lesser number.
-1/5, -1/7
And with our bigger ones, we have 1/3 and 1/2. 1/2 is the bigger number here, so that will be the last one. Let's also be sure to convert back to our original forms! Here is our order :
-0.2, -1/7, 1/3, 0.5
Have a wonderful day and keep on learning! :D
A dot plot shows results from a range of data, giving it coordiantes so you can plot it on a graph
Answer:
Systolic on right

Systolic on left

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.
Step-by-step explanation:
Assuming the following data:
Systolic (#'s on right) Diastolic (#'s on left)
117; 80
126; 77
158; 76
96; 51
157; 90
122; 89
116; 60
134; 64
127; 72
122; 83
The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

And the best estimator is 
Systolic on right
We can calculate the mean and deviation with the following formulas:
[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

For this case we have the following values:

So then the coeffcient of variation is given by:

Systolic on left
For this case we have the following values:

So then the coeffcient of variation is given by:

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.