If you and a friend order two veggie burgers one salad one fry and two coffees what is the total bill was 4% tax and 15% tip

Mathematics

1 answer:

zubka84 [21]2 years ago

5 0

($3.25x2)+$2.25+$1.50+($0.90x2)=$13.05
$13.05=100%
119%=$15.529=$15.53

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According to the fundamental theorem of algebra, how many zeros does the function f(x) = 4x3 − x2 − 2x + 1 have?

jarptica [38.1K]

Answer: 3 zeroes.

Explanation:-

The fundamental theorem of algebra states that any polynomial with degree m>0 and complex coefficients has atleast one complex root.
Corollary of fundamental theorem states that for any polynomial with degree m>0 has exactly m solutions.

The given function is $f(x)=4x^3-x^2-2x+1$

Because it is a polynomial function with degree 3>0 , Therefore by corollary of fundamental theorem of algebra , it has 3 zeroes.

8 0

3 years ago

Read 2 more answers

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

7 0

2 years ago

Elena and Jada are 25 miles apart when they start moving toward each other. Elena runs at a constant speed of 6 mph and Jada wal

Setler [38]

Answer:

The Time taken by Elena and Jade to meet up is 2.5 hours

Explanation:

Given,

Elena moves with a speed of 6mph while Jada walks at a speed of 4 mph

Also, Distance can be calculated by the formula

$Distance = Speed * Time$

To find out the Total speed, i.e., speed of both Elena and Jada as both of them are walking in opposite direction we should add the speed of both the persons, if in same direction we should subtract the values

Here it will be: $6 + 4$ = 10mph