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vlada-n [284]
3 years ago
6

What is the slope of the line that passes through the points (9,−10) and (3,−13)? Write your answer in simplest form.

Mathematics
2 answers:
Darina [25.2K]3 years ago
6 0

Answer:

1/2.

Step-by-step explanation:

The slope = rise/run

= (-13 - (-10)) /   (3 - 9)

= -3 / - 6

= 1/2.

hoa [83]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-13-(-10))/(3-9)

m=(-13+10)/-6

m=-3/-6

m=3/6

m=1/2

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Let f(x)=−3x. The graph of f(x) ​is transformed into the graph of g(x) by a vertical stretch of 4 units and a translation of 4 u
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Evaluate the expression x³ when x=0.2
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What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









4 0
3 years ago
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