2 years ago

Which of the following represents a radius of the circle?

Mathematics

1 answer:

Olegator [25]2 years ago

4 0

Mn is the correct answer

You might be interested in

The following are the ages (years) of 5 people in a room:

Gnom [1K]

Step-by-step explanation:

Mean=sum of terms/ number of terms

22+23+25+17+18/5

105/5

Finding the age of the sixth person

105+x/6=24

105+x=24x6

105+x=144

x=144-105

x=39

7 0

2 years ago

The number of donuts produced by a machine is directly proportional to the time the machine runs . The machine produces 380 donu

mrs_skeptik [129]

Answer:

855 donuts

Step-by-step explanation:

380/20 = 19 donuts per minute

19 × 45 = 855

5 0

2 years ago

A letter in the word COURAGE is chosen at random, then a coin is tossed three times. How many outcomes are possible?

RideAnS [48]

Answer:

I think about 10

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Angle ACB is an inscribed angle of circle P. What is the measure of angle ACB if arc MAB is equal to 50 degrees?

Yakvenalex [24]

∠ACB is an inscribed angle, so

m∠ACB= (1/2)mAB =(1/2)*50=25⁰

m∠ACB= 25⁰

3 0

2 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago