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kati45 [8]
3 years ago
6

What is the circumference of the given circle in terms of pi

Mathematics
1 answer:
elixir [45]3 years ago
7 0
The answer is 30pi in.
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Plug into calculator...
solve(2(-y+1)-3y=-30,y)
y=6.4

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Write an equation in slope intercept form (0,3) (3,0)​
taurus [48]

Answer:

y=-1x+3

Step-by-step explanation:

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What is 6 plus 2 (x plus 4) divided by 2
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A mailbox on the street is 600 feet from the top of a building. From the mailbox looking up to the tops of that building and a s
VLD [36.1K]

Answer:

  • first building: 479.2 ft
  • second building: 704.2 ft

Step-by-step explanation:

Label the mailbox viewpoint, the top of the first building, and the top of the second building points M, A, and B, respectively.

Consider the triangle MAB. You are told length MA is 600 ft, and length AB is 800 ft. Side AB is opposite the 67° angle at M, so we can use the Law of Sines to find other measures of that triangle. Specifically, we want to know the distance MB.

  sin(B)/MA = sin(M)/AB

  sin(B) = (MA/AB)sin(M) = 600/800·sin(67°) ≈ 0.690379

  B ≈ 43.66°

Then the angle at A is ...

  180° -67° -43.66° = 69.34°

and the side MB can be found from ...

  MB/sin(A) = AB/sin(M)

  MB = (sin(A)/sin(M))AB = sin(69.34°)/sin(67°)·800 ≈ 813.2 . . . feet

__

Now, label points on the ground below A and B as A' and B'. This problem is asking for the heights AA' and BB'. Each of these is opposite the angle of elevation to points A and B, respectively, so can be found using the sine relation:

  sin(elevation to A) = AA'/MA

  AA' = MA·sin(elevation to A) = 600·sin(53°) ≈ 479.2 . . . ft

Similarly, ...

  BB' = MB·sin(elevation to B) = 813.2·sin(60°) ≈ 704.2 . . . feet

The first building is 479.2 ft tall; the second is 704.2 ft tall.

5 0
3 years ago
Describe the relationship among the lengths of the segments formed by the two secants. You may use words and/or an equation.
wolverine [178]

It is possible to find DH based on the stated theorem

<h3>Secant-secant rule:</h3>

This rule states that if two secants are drawn from an external point to a circle, then the product of the measures of one secant's external part and that entire secant is equal to the product of the measures of the other secant's external part and that entire secant.

Mathematically:

  • (CG+GE)CG = (CH+HD)CH

Given the following parameters

CG=4 in

CH=5 in

GE=6 in

Substitute to check if we can find DH

(4+6)*4 = (5+DH)*5

10*4 = 25 + 5DH

40 - 25 = 5DH

15 = 5DH
DH = 3in

Therefore it is possible to find DH based on the stated theorem

Learn more on secant-secant theorem here: brainly.com/question/10732273

4 0
2 years ago
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