Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?
1 answer:
Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and
Therefore segment NO is parallel to the segment KL.
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Answer: 18 cm^2
Step-by-step explanation:
There are four equal triangle and a rectangle.
Formula of a rectangle = b * h = 2*3 = 6
Formula of triangle = but there four of them so we times them by 4, this leaves us with 2 (b * h) = 2(2*3) = 12
Area of pentagon = area of all triangles + rectangle
Area of pentagon = 12 + 6 = 18
Hope this helps.