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3 years ago

Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?

Mathematics

1 answer:

Oliga [24]3 years ago

6 0

Segment NO is parallel to the segment KL.

Solution:

Given KLM is a triangle.

MN = NK and MO = OL

It clearly shows that NO is the mid-segment of ΔKLM.

By mid-segment theorem,

The segment connecting two points of the triangle is parallel to the third side and is half of that side.

⇒ NO || KL and $NO = \frac{1}{2}KL$

Therefore segment NO is parallel to the segment KL.

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Determine whether the following function is linear or quadratic. Identify the quadratic, linear, and constant terms. f(x)=3x(x−1

Nataliya [291]

It is quadratic, because the highest degree for x is 2, x². Expand the expression and you'll see: f(x)=3x²-3x-3x-7
simplify: f(x)=3x²-6x-7
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3 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

See comment for complete question.

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

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2 years ago

HELP PLEASE!! ASAP If triangles ABC and DEF are similar, what is y? Show your work.

Ivenika [448]

Answer:

y = 18

Step-by-step explanation:

Since the triangles are similar, the corresponding sides are in proportion, that is

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14y = 252 ( divide both sides by 14 )

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3 0

3 years ago

Read 2 more answers

A parallelogram with a base of y units and a height of x units is changed to have a new base of 3y units and a height of 2x unit

nataly862011 [7]

The formula for the area of a parallelogram is

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So if the original area was 47units², then the new area would be

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3 years ago

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Novosadov [1.4K]

Answer:

I would say A

Step-by-step explanation:

hmu if you need more help

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3 years ago