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3 years ago

Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?

Mathematics

1 answer:

Oliga [24]3 years ago

6 0

Segment NO is parallel to the segment KL.

Solution:

Given KLM is a triangle.

MN = NK and MO = OL

It clearly shows that NO is the mid-segment of ΔKLM.

By mid-segment theorem,

<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>

⇒ NO || KL and $NO = \frac{1}{2}KL$

Therefore segment NO is parallel to the segment KL.

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Vsevolod [243]

I don’t really know exactly to what degree you need to put in your solution. But I rounded to the nearest tenth degree.
A = 112 degrees
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HOW TO SOLVE:
c= law of sines, so c/sin(40) = 14/sin(28), multiply both sides by sin(40) so c can be isolated and solved for. c = 14sin(40)/sin(28). Plug into calculator then get answer. c is approximately 19.2.
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3 years ago

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Step-by-step explanation:

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Answer:

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