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alina1380 [7]
4 years ago
15

Eli attended a concert. The decibel level of the music averaged 110 decibels but varied by 28 decibels from the average. Enter a

nd solve an absolute-value inequality to find the decibel range. Use d as your variable.
Mathematics
1 answer:
musickatia [10]4 years ago
8 0

Answer:

The decibel range is   82\leq d\leq 138

Step-by-step explanation:

Let

d -----> the decibel level of the music

we know that

The absolute value of the difference of the decibel level of the music and its average, must be less than or equal to 28 decibels

so

The absolute value that represent this problem is

\left|d-110\right|\le28

Solve the absolute value

<em>First solution (positive)</em>

+(d-110)\le28

Adds 110 both sides

d\le28+110

d\le138

<em>Second solution (negative)</em>

-(d-110)\le28

Multiply by -1 both sides

(d-110)\ge-28

Adds 110 both sides

d\ge-28+110

d\ge82

therefore

The decibel range is

82\leq d\leq 138

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Answer:

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Step-by-step explanation:

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Hit and trial error method.

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Now factor x^2+9x+18

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Hello!

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