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The number of bits in the physical address is 26 bits. The number of entries in a page table is entries. The size of the page table in a one-level paging scheme is 4MB.
What is paging in Operating System?</h3>
Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.
We are given the following parameters:
- 32-bit logical address
- Page size = 4 KB =
- Size of each Page table entry = 4 bytes
Suppose the system supports physical memory size = 64 MB =
Thus, the number of bits in the physical address is computed as:
=
= 26 bits
The number of entries in a page table = logical address space size/page size
The number of entries in a page table
entries
In a one-level paging scheme, the size of the table is:
= entire no. of page entries × page table size
=
= 4 MB
b.
suppose that this system supports up to 2^30 bytes of physical memory.
- The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.
Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.
- This is called the Multi-Level Paging system.
Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is entries, and the size of the page table in a one-level paging scheme is 4MB.
Learn more about Paging in Operating System here:
#SPJ1
Answer:
Total number of character comparison = 43
Explanation:
Using the Brute force algorithm
The string of n characters is known as text, and the string of m characters is known as the pattern.
From the given information:
The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED
The pattern (m) = GANDHI
The total no of characters that we have in the text = 47
The total number of characters in pattern = 6
For a brute force algorithm;
Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1
= 47 – 6 + 1
= 47 – 5
= 42
Thus; the algorithm will attempt the trial 42 times.
Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.
On each attempted trial, the algorithm will make one unsuccessful comparison.
However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.
Hence, we can calculate the total number of character comparison as follows:
Total number of character comparison =
Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )
Total number of character comparison = 41 + 2
Total number of character comparison = 43