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Rina8888 [55]
3 years ago
11

James works as a waiter. He served meals with bills of $23.59, $40.65, $30.50, and $15.68. If his total for tips was $17.67, wha

t percent tip did he receive for serving these meals? Round your answer to the nearest percent.
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
6 0

Answer:

16%

Step-by-step explanation:

To find the percent, add the total for each meal to find the total dollars spent.

23.59 + 40.65 + 30.50 + 15.68 = 110.42

Divide the tip amount 17.67 by 110.42.

17.67/110.42 = 0.16

Multiply the decimal by 100 to convert to a percent.

0.16*100 = 16%

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Percent between 230.59 and 243.24
yaroslaw [1]
All we have to do here is subtract 243.24 from 230.59 to get our percentage.
243.24 - 230.59 = 12.65%
3 0
4 years ago
Read 2 more answers
1. A man has 5 grandchildren, 4 girls and 1 boy. He thinks this is unusual. If the probability that any child born
mojhsa [17]

Answer:

6.25%

Step-by-step explanation:

To know the final probability that this has happened, we must multiply the probability of each event, they tell us that the probability that it is a girl is 1/2 and this happened 4 times, therefore:

(1/2) ^ 4 = 0.0625

that is, the probability that 4 girls are born is 6.25%

an unusual probability is considered when it is less than 5%, therefore, although it approaches this figure, it is not unusual

4 0
3 years ago
The thicknesses of 81 randomly selected aluminum sheets were found to have a variance of 3.23. Construct the 98% confidence inte
Yuliya22 [10]

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

[(n - 1)\times S^{2}  /  X^{2}  \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2}  / X^{2} 1- \alpha/2, n- 1 ]

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

X^{2}_{[\alpha/2, n - 1]}   = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0
3 years ago
A bag can hold 1 1/2pounds of flour. if Mimi has 7 1/2pounds of flour, then how many bags of flour can Mimi make?
Naily [24]

Answer:

5 BAGS OF FLOUR

7 1/2 ÷ 1 1/2 = 5

Based on the given conditions, formulate: 7 1/2 / 1 1/2 Find common denominator and write the numeral.

6 0
2 years ago
Read 2 more answers
(6z 2 - 4z + 1)(8 - 3z).
Yakvenalex [24]
Distributive property
a(b+c)+ab+ac
a(b-c)=ab-ac

(6z^2-4z+1)(8-3z)
move for nicety
(8-3z)(6z^2-4z+1)
distribute
8(6z^2-4z+1)-3z(6z^2-4z+1)=
48z^2-32z+8-18z^3+12z^2-3z=
-18z^3+48z^2+12z^2-32z-3z+8=
-18z^3+60z-35z+8
7 0
3 years ago
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