Answer:
a1 = 6
a2 = 15
a3 = 24
a4 = 33
Step-by-step explanation:
Let k =1
a1 =-3 +9(1) = -3 +9 = 6
Let k = 2
a2 = -3 +9(2) =-3+18 = 15
Let k =3
a3 =-3 +9(3) = -3 +27 = 24
Let k = 4
a4 = -3 +9(4) =-3+36 = 33
Answer:
-32
Step-by-step explanation:
10–{22–[(−9)+(−11)]}
Work inside out
10–{22–[(-20)]}
Subtracting a negative is adding
10–{22+20}
10 - 42
-32
Resolviendo el sistema de ecuaciones veremos que:
- niña = 23kg
- niño = 28kg
- perro = 18kg.
<h3>
¿Como resolver el sistema de ecuaciones?</h3>
Aqui tenemos el sistema de ecuaciones:
Niña + niño = 51kg
Niño + perro = 46 kg
Niña + perro = 41kg
Para resolver esto, lo primero que debemos hacer es aislar una variable en una de las ecuaciones, por ejemplo, podriamos aislar "perro" en la tercera:
perro = 41kg - niña
Ahora reemplazamos eso en la segunda para obtener:
niño + (41kg - niña) = 46kg
niño - niña = 46kg - 41kg = 5kg
niño = niña + 5kg
Ahora logramos obtener la variable "niño" en terminos de la variable "niña". Podemos reemplazar esto en la primera ecuacion del sistema.
niña + niño = 51kg
niña + (niña + 5kg) = 51kg
2*niña = 51kg - 5kg = 46kg
niña = 46kg/2 = 23kg.
Ahora que sabemos esto, usamos las otras ecuaciones para encontrar el peso del niño y el perro:
niño = niña + 5kg = 23kg + 5kg = 28kg
perro = 41kg - niña = 41kg - 23kg = 18kg.
Sí quieres aprender más sobre sistemas de ecuaciones, puedes leer:
brainly.com/question/17174746
Answer:
24 feet cubed
Step-by-step explanation:
When comparing the volume formula for a cone and the volume formula for a cylinder, a cone is 1/3 of a cylinder. Therefore, divide 72 by 3 to get the volume of a cone with the same base and height. It would not be 24 pi feet cubed because 72 feet cubed is already multiplied by the pi.
Answer:
Step-by-step explanation:
Given that special deck of cards has 20 cards. Nine are green, seven are blue, and four are red. When a card is picked, the color of it is recorded. An experiment consists of first picking a card and then tossing a coin
A) Sample space will have Green, Head, or Green, Tail .... Red, head, red, tail
No of elements in sample space = no of colours x no of outcomes in coin toss
= 4x2 = 8
B) A= getting (RT)
P(A) = Prob of getting red card and tail on coin
= P (R) *P(T)
=
C) B be the event that a green or blue is picked, followed by landing a tail on the coin toss
B = getting green card and tail
Getting green card tail is mutally exclusive with red card and tail as there is no common element between green and blue.
D) C= red or green card is picked followed by tail.
Here A and C have a common element as getting red and tail. So not mutually exclusive
