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Nostrana [21]
3 years ago
9

48x3 +128x2 − 75x − 200 factor

Mathematics
1 answer:
frosja888 [35]3 years ago
3 0
The answer is -25(3x-8)
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2. Mrs. Jones' science class is planting sunflowers in the school garden. Her class
Levart [38]

Answer:

1 sunflower

Step-by-step explanation:

Start at 15 then go to the left of the line graph. After count how many X there are which there is one.

6 0
2 years ago
Joseph has started completing the square on the equation 3x^2-7x+12=0. He has worked to the point where he has the expression x^
Dima020 [189]
Starting with <span>3x^2-7x+12=0, we divide all four terms by 3, resulting in the following factored form:
</span><span>
3(</span><span>x^2-[7/3]x+4)=0.
</span><span>
Since 3 cannot equal 0, we can focus on the following:

x^2 - 7/4 x =-4

This completes the assignment (describe Joe's steps up to this point).



If you wish to go further:

Next, take HALF of the coefficient of x and square your result:

(-7/[4][2])^2 = 49/64

Add this to both sides of </span>x^2 - 7/4 x =-4:    <span>x^2 - 7/4x + 49/64 =-4+49/64

Rewrite the left side as (x-7/8)^2 and the right side as 49/64 - 256/64

Simplify the right side by combining these terms:  -207/64

Then x-7/8 = plus or minus (1/8)sqrt(-207)

Next, x = 7/8 plus or minus (1/8)*i*</span>√207, or

          7 plus or minus i*√207
 x = ----------------------------------
                         8
4 0
3 years ago
Suppose you can get a higher interest rate on your savings if you maintain a balance of at least $1000 in your savings account.
maksim [4K]
1058+44.50 =1102.5
1102.5-1000=102.5
102.5 is your anwser

4 0
3 years ago
Read 2 more answers
10. Contacts. Assume that 30% of students at a university
jonny [76]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) A normal model with mean 0.3 and standard deviation of 0.0458 should be used.

b) There is a 0.2327 = 23.27% probability that more than one third of this sample wear contacts.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 30% of students at a university wear contact lenses, hence p = 0.3.
  • We randomly pick 100 students, hence n = 100.

Item a:

np = 100(0.3) = 30 \geq 10

n(1 - p) = 100(0.7) = 70 \geq 10

Hence a normal model is appropriated.

The mean and the standard deviation are given as follows:

\mu = p = 0.3

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.3(0.7)}{100}} = 0.0458

Item b:

The probability is <u>1 subtracted by the p-value of Z when X = 1/3 = 0.3333</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3333 - 0.3}{0.0458}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

1 - 0.7673 = 0.2327.

0.2327 = 23.27% probability that more than one third of this sample wear contacts.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

5 0
2 years ago
(5×10 exponent 8)/(2×10 exponent 6)​
iogann1982 [59]
500,000,000 and 2,000,000

10 exponent 8 is 100000000 because it has 8 0s
multiply that by 5 to get 500,000,000

10 exponent 6 is 1000000 because it has 6 0s
multiply by 2 to get 2,000,000
3 0
3 years ago
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