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3 years ago

Please help me out! :)

Mathematics

1 answer:

skad [1K]3 years ago

8 0

3x-11=x+23
-x -x
2x-11=23
+11 +11
2x=34
x=17

3(17)-11 17+23
=40 =40

explanation ;
you would equal them because they are congruent . & you substitute x for 17 in each equation to find out the degrees of both of the angles :)

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Tim and Tom are painters. Tim and Tom are painting a crate. Tom paints 10 sq ft per minute. They painted a particular crate in 1

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Tom-------------- >10 sq ft per minute

Tim------------------- >3.5*10=35 sq ft per minute

Both painters (10+35)=45 sq ft per minute

let's assume a cubic unit crate----------> V1=1*1*1=1 feet3

the total surface of the cube is S1=6*(1*1)=6 sq ft

if the volume of the cube increases twice

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And the S2=6*(2^(1/3)* 2^(1/3)=9.5244 sq ft

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For the crate V2------------- > take 1.5874 days

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Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: 3 tires are blemished.

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: 2 tires are blemished.

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: 1 tires are blemished.

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: No tires are blemished.

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

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