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Firlakuza [10]
2 years ago
7

Please help

Mathematics
1 answer:
Ne4ueva [31]2 years ago
3 0

Answer:x=18

Step-by-step explanation:

if she deposites 40 every week 40 times 18 is 720 so in 18 weeks she can have a t.V

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What is the equation of the following linear funchon?
juin [17]

Answer:

3x+8

Step-by-step explanation:

linear function formula ax+b

when x=3 3a+b=17 and when x=6 6a+b=26

3a=9 a=3,

when x=3 3.3+b=17 9+b=17 b=8

3x+8

3 0
2 years ago
Probability help please with questions 1, 2, 3, 4, 5 and 7 please? Thanks in advance! I appreciate your time so much!
Katarina [22]
1. 3/6 = 1/2
2. 5/6
3. 3/6 : 3/6 = 3 : 3
4. 3/6 : 3/6 = 3 : 3
5. 5/6 : 1/6 = 5 : 1
7. 3/6 × 1/2 = 1/4
7 0
3 years ago
Subtract. <br> –84 – 55<br> a. –29<br> b. –139<br> c. 29<br> d. 139
Hitman42 [59]
-84 - 55 = -139 Here both have same sign (-) so u add and put the common sign(-) .... So the answer is option B ( -139)... Hope it helps!!!
8 0
2 years ago
Jackson earns $25 per hour as a tutor at the college library. he set a weekly spending budget of $130 a week and push the remain
a_sh-v [17]

Answer:

Jackson should work at least 8 hours this week to achieve his target.

Step-by-step explanation:

Jackson's hourly income = $25

His weekly spending budget = $130

Minimum amount to be pushed to the savings account = $50

So, minimum total amount Jackson should earn this week = 130 + 50 = 180

Number of hours to work this week = \frac{Minimum total amount}{hourly income}

= \frac{180}{25}

= 8 rounded to next integer

Hence, Jackson should work at least 8 hours this week to achieve his target.

6 0
3 years ago
Determine the radius of convergence of the following power series. Then test the endpoints to determine the interval of converge
tresset_1 [31]

Answer:

Radius of the convergence is R = \frac{1}{21}

and,

The Interval of convergence is -\frac{1}{21}

Step-by-step explanation:

Given function : Σ(21x)^k

Now,

Using the ratio test, we have

R = \lim_{n \to \infty} |\frac{21x^{k+1}}{21x^{k}}|

or

R = \lim_{n \to \infty} |\frac{21x^{k}\times21x^{1}}{21x^{k}}|

or

R = \lim_{n \to \infty} |21x^{1}|

now,

for convergence R|x| < 1

Therefore,

\lim_{n \to \infty} |21x^{1}| < 1

or

-\frac{1}{21}

and,

Radius of the convergence is R = \frac{1}{21}

and,

The Interval of convergence is -\frac{1}{21}

8 0
3 years ago
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