Question

simply algebra question--i keep getting it wrong, but if you could solve it i should hopefully understand what ive been messing up on

Answer 1

Start with

$\dfrac{5-2x}{3}+1-\dfrac{3x-2}{5}=-x$

Multiply both sides by 15 to get rid of denominators:

$5(5-2x)+15-3(3x-2)=-15x$

Expand the left hand side:

$25-10x+15-9x+6=-15x$

Move all terms involving x to the left and all numbers to the right:

$-10x-9x+15x=-25-15-6$

Sum like terms:

$-4x=-46$

Divide both sides by -4:

$x=\dfrac{46}{4}=\dfrac{23}{3}$