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2 years ago

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pppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

1 answer:

likoan [24]2 years ago

8 0

I think it’s an regular because it looks like an rectangle

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X^4-6x^2+8(Type 2 of quadratic equation)

Alex Ar [27]

Step-by-step explanation:

x⁴ - 6x² + 8

= (x² - 4)(x² - 2)

= (x + 2)(x - 2)(x² - 2).

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2 years ago

1, 8, 27, 64,____, ____, ____,...

kherson [118]

125 216 343
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2 years ago

12+3/5x−8−7/10x=?

Liono4ka [1.6K]

Answer:

−1 /10 x+4

Step-by-step explanation:

Group like terms

=3/5x-7/10x+12-8

add

-10x+12-8

1/10x=x/10

-x/10+12-8

−1 /10 x+4

If you need more help just ask

7 0

3 years ago

Solve for x.5(x – 10) = 30 – 15x

nlexa [21]

$5(x-10)=30-15x
$
$5x-50=30-15x
$
$20x=30+50$
$x=4.$

6 0

3 years ago

A data set includes 108 body temperatures of healthy adult humans having a mean of 98.3degrees°F and a standard deviation of 0.6

mylen [45]

<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n=106

Sample mean : $\overline{x}=98.3^{\circ}\ F$

Standard deviation : $\sigma= 0.69^{\circ}F$

Significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=2.576$

Then , 99% confidence interval estimate of the mean body temperature of all healthy humans will be :-

$98.3\pm (2.576)\dfrac{0.69}{\sqrt{106}}\\\\\approx98.3\pm0.173=(98.3-0.173,\ 98.3+0.173)=(98.127,\ 98.473)$

Since 98.6 is higher than the upper limit of the confidence interval (98.473), then this suggest that the mean body temperature could be lower then 98.6 degrees.

The best estimate of population mean is always the sample mean. $\mu=\overline{x}=98.3^{\circ}\ F$

7 0

3 years ago