All categories

3 years ago

Expanded form using fractions 1/100

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

Answer:

Standard form: 1

Step-by-step explanation

expanded notation form: 1

expanded factors form: 1x1

expanded exponential for 1x 10^0

You might be interested in

I have to find the slope for 4. ASAP please help

Lorico [155]

Given:

The objective is to find the slope of the straight line.

Explanation:

The general equation to find the slope is,

$m=\frac{y_2-y_1}{x_2-x_1}$

Let's consider two coordinates from the graph.

$\begin{gathered} (x_1,y_1)=(0,0) \\ (x_2,y_2)=(-1,5) \end{gathered}$

On plugging the values in the equation of slope,

$\begin{gathered} m=\frac{5-0}{-1-0} \\ m=-5 \end{gathered}$

Hence, the slope of the straight line is -5.

3 0

1 year ago

WILL GIVE BRAINLIEST The angle of elevation from Ben to the top of a telephone pole is 62 degrees. If Ben is standing 8 feet fro

MrRissso [65]

Answer: The height of the telephone pole = $15.046

Step-by-step explanation:

Given: Angle of elevation= 62 degrees.

Distance of Ben from the base of the pole = 8 feet

According to trigonometry, we have

$\tan x=\dfrac{\text{side opposite to x}}{\text{side adjacent to x}}$

i.e.

$\tan 62^{\circ}=\dfrac{\text{ height of the telephone pole}}{8}\\\\(1.880726)=\dfrac{\text{ height of the telephone pole}}{8}\\\\\text{ Height of the telephone pole} = 8\times 1.880726\approx15.046$

Hence, The height of the telephone pole = $15.046

4 0

2 years ago

Please also explain how you did it! Thank you

Tasya [4]

Answer:

66 degrees

Step-by-step explanation:

360 degrees in a circle

102 and 144 make up the circumference of LPN

LMN however is still to be determined... which is 360-(102+144) = 114

Therefore, LMN = 114 degrees. Using a thereom (I forget which one), the corresponding angle to LMN is LPN.

To find angle LPN (180-114) = 66

8 0

2 years ago

If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. see if those v

kkurt [141]

a=4 , b=3 These values make the equation true .

<u>Step-by-step explanation:</u>

Here we have , If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. We need to find if those values make the equation true . Let's find out:

We have the following equation:

-(a/b) = (-a)/b = a/(-b) , Let a=4 , b=3 , So

⇒ $-(a/b) = (-a)/b = a/(-b)$

⇒ $-\frac{a}{b} = \frac{-a}{b} = \frac{a}{-b}$

⇒ $-\frac{4}{3} = \frac{-4}{3} = \frac{4}{-3}$

⇒ $-\frac{4(-1)}{3} = \frac{-4(-1)}{3} = \frac{4(-1)}{-3}$ { Multiplying by -1 }

⇒ $\frac{4}{3} = \frac{4}{3} = \frac{4}{3}$

Therefore , These values make the equation true .

7 0

3 years ago

21 POINTS!! Thank you so much!! There’s also things on my page worth lots points points as well! So if you could help with those

Art [367]

Answer:

Second one

third one

fifth one

last one

Step-by-step explanation:

Based on the x intercepts we can write

a(x+1)(x-5)

where a is some constant

solve for a by plugging in some coordinates

let's plug in (1,-8)

-8=a(1+1)(1-5)

-8= -8a

a=1

therefore the quadratic is (x+1)(x-5)

expand this

x²-4x-5

To find out where something is decreasing/increasing it's easiest to take the first derivative

x²-4x-5= 2x-4

set this equal to 0

2x-4=0

2x=4

x=2

Which means that our two intervals are

(-∞,2)U(2,∞)

plug in any values in the intervals to see whether or not the function is increasing/decreation

Let's plug in 0 for (-∞,2)

2(0)-4

-4

It's negative so it's decreasing on this interval

DO the same thing with the other one

let's plug in x=3

2(3)-4

this is positive so it's increasing on this interval

Go back to the critical value of x=2 and plug this into the equation to find the max/min

(2+1)(x-5)= -9

This is a minimum because the cofeccient for the degree is positive

For the limit one notice that we have a positive, even degree which means the end behavior is positive, positive

what this means is as x approaches negative infinity it's infinity

and as x approaches infinity it's infinity

6 0

2 years ago