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Nady [450]
3 years ago
9

Solve 1 And 2 Step Equations.

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0
W 678876? Tried the same place to see what your food is
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Leah makes an origami photo frame to showcase her favorite family picture. The size
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Answer:

28 feet

Step-by-step explanation:

3.5 x 8 = 28

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Solve the equation and enter the value of x below.<br> x+ (9) = -15<br> X=
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3 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
I need the answers asappp!!!!
labwork [276]

Answer:

Part A:y=4,1,0,1,4

Step-by-step explanation:

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5 0
3 years ago
2 divided by one third
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2 / 1/3
= 2* 3/1
= 2*3
= 6
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3 years ago
Read 2 more answers
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