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2 years ago

What is 21divided by 7/4

Mathematics

1 answer:

Ainat [17]2 years ago

3 0

21/1 divided by 7/4 = 21/1 x 4/7 = 12.

Hope this helped my guy.

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Number 1 d pleaseeeeee

PIT_PIT [208]

Find 25 seconds in the table. That's between 20 and 30, right? So, find the median between 19 and 28:
19 + 28
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That is around 24 deep knee squats per 25 seconds. Now, use the same method for 65 seconds:

51 + 58
---------- = 54.5
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That is around 55 deep knee squats per 65 seconds.
Now, explain the method using words. You might wanna use the words "average" or "mean" to describe that process above.

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2 years ago

You start at (4, 4). You move up 1 unit and left 6 units. Where do you end?

Citrus2011 [14]

Answer: (10,5)

Step-by-step explanation:

add 6 do the x value

then add 1 to the y value

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3 years ago

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Surface area of B is 40.32<br> surface area of a is 28

Nezavi [6.7K]

Answer:

Step-by-step explanation:

what's the question exactly?

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2 years ago

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How do you plot a fraction on a graph that only allows whole numbers?

klio [65]

Answer:

Depends, rise over run could be considered a fraction, or if it's a number that has a whole number like one and 3/4 then you just plot the point to the best of your ability. In other words guess.

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2 years ago

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A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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3 years ago