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blagie [28]
4 years ago
11

X values of a logarithmic function will always be...

Mathematics
1 answer:
Ierofanga [76]4 years ago
5 0
They will always be positive :)
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Round to the nearest thousand . Use the number line to model your thinking
ivolga24 [154]

Answer:

Step-by-step explanation:

the line grath is your answer

YOU WELCOME

8 0
3 years ago
(7x+3) (10x-14) HELP PLEASE
liubo4ka [24]

Answer:

70x^{2}+30x-140

Step-by-step explanation:

(7x+3) (10x-14)

70x^{2}-98+30x-42

70x^{2}+30x-42-98

70x^{2}+30x-140

7 0
3 years ago
Read 2 more answers
How many outcome sequences are possible when a die is rolled 4 times where we say for instance that the outcome is 3 4 3 1 if th
STatiana [176]

Answer:

the possible outcome sequences when a die is rolled 4 times is 1296

Step-by-step explanation:

 Given the data in the question;

a die is rolled 4 times

and outcomes are { 3, 4, 3, 1 }

we know that; possible number of outcomes on a die is n = 6{ 1,2,3,4,5,6 }

Now when we roll a die lets say, r times

then the total number of possible outcomes will be;

N = n^r

given that; r = 4

Hence if we roll a die 4 times;

Total number of possible outcome N = 6⁴

N = 1296

Therefore, the possible outcome sequences when a die is rolled 4 times is 1296

3 0
3 years ago
-4/5+7/12 simplify the expression
miss Akunina [59]

Answer:

\frac{-13}{60}

Step-by-step explanation:

So lets get the denominators the same:

\frac{-4}{5} +\frac{7}{12}

=\frac{-48}{60} +\frac{35}{60}

=\frac{-13}{60}

Hoped I helped, have a nice day!

And please help: brainly.com/question/22129776

5 0
3 years ago
There is a bag filled with 2 blue, 4 red and 5 green marbles.
Vinil7 [7]
<h3>Answer: 45/121</h3>

=========================================

Work Shown:

2 blue, 4 red, 5 green

2+4+5 = 11 total

P(blue) = probability of getting one blue marble

P(blue) = (number of blue)/(number total)

P(blue) = 2/11

A = P(2 blue) = (2/11)*(2/11) = 4/121

P(red) = 4/11

B = P(2 red) = (4/11)*(4/11) = 16/121

P(green) = 5/11

C = P(2 green) = (5/11)*(5/11) = 25/121

Add the values of A,B, and C to get the probability of getting two of the same color

A+B+C = 4/121+16/121+25/121 = 45/121

This is approximately equal to 0.3719 which is roughly a 37.19% chance of happening

Side note: we can add A,B, and C because they are mutually exclusive events.

6 0
4 years ago
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