Answer:
-√2+√6/4
Step-by-step explanation:
To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
The area of the square is 9 in^2
The side of a square is the square root of the area.
Side of square = √9 = 3 inches.
The side of the square is the diameter of the inscribed circle.
Circumference of a circle is PI x diameter.
Circumference of inscribed circle = 3.14 x 3 = 9.42 inches
The diameter for the circumscribed circle would be the diagonal of the square which is 3√2 = ( Side length x √2) ≈ 4.2426
The circumference = 3.14 x 3√2 = 13.321
Find the ratio between the two circles:
Circumscribed / inscribed =
13.321 / 9.42 = 1.41
It’s would be h=6
hope this helped
Answer:
77.77 or 78%
Step-by-step explanation:
She got 35/45 so
35 divided by 45 is 0.777777778
0.777777778 x 100 = 77.7777778
77.77% or 78%
