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2 years ago

The equation x+53=15 can be solved by performing two operations on both sides.

1 answer:

3 0

Hey!

You're right! This equation can definitely be solved by performing two operations on both sides. Let me show you how it's done.

First, let's write out our equation.

Original Equation :
x + 53 = 15

Now that that's done, we'll be performing two operations on both sides. The operation we'll want to do is subtracting both sides of the equation by 53. We do this to get x on its own.

Original Equation :
x + 53 = 15

New Equation {Added Subtract 53 to Both Sides} :
x + 53 - 53 = 15 - 53

Now we have to solve the equation. Let's do the left side first.

Left Side of the Equation :
x + 53 - 53

Left Side of the Equation {Solved} :
x

Now, we'll solve the right side of the equation.

Right Side of the Equation :
15 - 53

Right Side of the Equation {Solved} :
-38

Now we can put both solutions to both sides of the equation together.

New Equation :
x = -38

Since this cannot be simplified any farther, this is our final answer. And that's it!

So, now we know that in the equation x + 53 = 15, x = -38

Hope this helps!

- Lindsey Frazier ♥

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2 years ago

What is 1 + 1 if the answer is 2 then why is it 2

maks197457 [2]

Answer:

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Step-by-step explanation:

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2 years ago

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Find the generating function for the sequence 1,1,1,2,3,4,5,6,....

marin [14]

Answer:

$P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1$ [/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

$1,1,1,2,3,4,5,6,...$

the generating function would be

$P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\$

we can multiply P(x) by x to get

$xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...$

Note that

$P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\ \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)$

which for $\mid x \mid < 1$ can be rewritten as

$(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}$

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2 years ago

What is the answer to this problem (x+3)(x+5)

klasskru [66]

Easy, showing work,

using the method FOIL (First,Outer,Inner, Last)

Take, (x+3)(x+5) and multiply,

First,

x*x= $x^{2}$

Outer,

x*5=5x

Inner,

3*x=3x

Last,

3*5=15

Add the terms together,

$x^{2}$ +8x+15 ( $x^{2}$ +5x+3x+15)

Thus, your answer.

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Answer:

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