What is 6 3/4 x 3/5 A) 54/20 B) 75/12 C) 81/20 D) 9/4

riadik2000 [5.3K]

Answer:

you can simplify rations just like you simplify fractions. Whenever you are able to evenly divide both parts of the ratio with out changing the equation's answer, you are able to.

for example

if it were 3:6, you can simplify this by dividing these both by 3, leaving you with 1:2.

4 0

3 years ago

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On a piece of paper, graph y< -*x+2. Then determine which answer choice matches the graph you drew.

alisha [4.7K]

D. graph D

Explanation

Step 1

graph the function as a line

convert

$\begin{gathered} y$

to graph, find 2 coordianates

a) when x=0

$\begin{gathered} y=-\frac{3}{4}x+2 \\ y=-\frac{3}{4}\cdot0+2 \\ y=0+2,\text{ y=2} \\ so,\text{ we have P1(0,2)} \end{gathered}$

b) when

x=-4

$\begin{gathered} y=-\frac{3}{4}x+2 \\ y=-\frac{3}{4}\cdot-4+2 \\ y=3+2 \\ y=5 \\ P2(-4,5) \end{gathered}$

now, using two points draw a line

Step 2

we are looking fro values under this line, so the answer is

D. graph D

7 0

1 year ago

Help me with these please

olchik [2.2K]

Step-by-step explanation:

(1) y = x e^(x²)

Take derivative with respect to x:

dy/dx = x (e^(x²) 2x) + e^(x²)

dy/dx = 2x² e^(x²) + e^(x²)

dy/dx = (2x² + 1) e^(x²)

Take derivative with respect to x again:

d²y/dx² = (2x² + 1) (e^(x²) 2x) + (4x) e^(x²)

d²y/dx² = (4x³ + 2x) e^(x²) + 4x e^(x²)

d²y/dx² = (4x³ + 6x) e^(x²)

Substitute:

d²y/dx² − 2x dy/dx − 4y

= (4x³ + 6x) e^(x²) − 2x (2x² + 1) e^(x²) − 4x e^(x²)

= 4x³ + 6x − 2x (2x² + 1) − 4x

= 4x³ + 6x − 4x³ − 2x − 4x

= 0

(2) y = sin⁻¹(√x)

sin y = √x

sin²y = x

Take derivative with respect to x:

2 sin y cos y dy/dx = 1

sin(2y) dy/dx = 1

dy/dx = csc(2y)

Take derivative with respect to x again:

d²y/dx² = -csc(2y) cot(2y) 2 dy/dx

d²y/dx² = -2 csc²(2y) cot(2y)

Substitute:

2x (1 − x) d²y/dx² + (1 − 2x) dy/dx

= 2 sin²y (1 − sin²y) (-2 csc²(2y) cot(2y)) + (1 − 2 sin²y) csc(2y)

Use power reduction formula:

= (1 − cos(2y)) (1 − ½ (1 − cos(2y))) (-2 csc²(2y) cot(2y)) + (1 − (1 − cos(2y))) csc(2y)

= (1 − cos(2y)) (1 − ½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cos(2y) csc(2y)

= (1 − cos(2y)) (½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cot(2y)

= (cos(2y) − 1) (1 + cos(2y)) csc²(2y) cot(2y) + cot(2y)

= (cos²(2y) − 1) csc²(2y) cot(2y) + cot(2y)

= -sin²(2y) csc²(2y) cot(2y) + cot(2y)

= -cot(2y) + cot(2y)

= 0

8 0

3 years ago

Solve for x. 2x = 15 + x A: x = -15 B: x = 15 C: x = -15/2 D: x = 15/2

Ulleksa [173]

2x = 15 + x

First, our goal is to get 'x' to equal something by itself. To do so, we will have to do everything on one side. Let's subtract 'x' from each sides.
$2x - x = 15$

Second, our next step is to subtract '2x - x'. Since 'x' is basically considered (1), it will equal 'x'.
$x = 15$

Answer: $\fbox { x = 15 }$

3 0

4 years ago

2u+7u=81 simplify your answer as much as possible

jenyasd209 [6]

2u+7u=9u
9u=81
Divide both sides
U=9

7 0

3 years ago

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