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Nikolay [14]
3 years ago
8

Lines AB and CD are parallel. Find the measures of the three angles in triangle ABF.

Mathematics
2 answers:
Dovator [93]3 years ago
5 0

Answer:

these nuts ha gotdezz

Step-by-step explanation:

nevsk [136]3 years ago
3 0

A = 42°

B= 23°

F = 115°

Step-by-step explanation:

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What has a sum of 100 and a difference of 80 help me please
irga5000 [103]

Answer:

90 and 10

Step-by-step explanation:

90 + 10 = 100

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6 0
3 years ago
The mean student loan debt for college graduates in Illinois is $30000 with a standard deviation of $9000. Suppose a random samp
Nataly [62]

Answer:

the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

Step-by-step explanation:

Given that:

Mean = 30000

Standard deviation = 9000

sample size = 100

The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:

P(31000 < X < 33000) = P( X \leq 33000) - P (X \leq 31000)

P(31000 < X < 33000) = P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P(Z \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{3000}{\dfrac{9000}{10}}}) -P(Z \leq \dfrac{1000}{\dfrac{9000}{10}}})

P(31000 < X < 33000) = P( Z \leq 3.33)-P(Z \leq 1.11})

From Z tables:

P(31000 < X

P(31000 < X

Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

8 0
3 years ago
Help Help! Now help! ASAP!I’ll make you brainly now please
hammer [34]

Answer:

re08uwahrewrai098nyryvrhheuaviufvsdsavad <<< Don't do this please

42.3 meters

3 0
3 years ago
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