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Grace [21]
3 years ago
14

Which number in the monomial 125x^18 y^3 z^25 need to be changed to make it a perfect cube

Mathematics
1 answer:
Serhud [2]3 years ago
6 0
The power of 25 on the variable z needs to be changed. It has to be divisible by 3.
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What operation should be used to solve the equation 153=g+45
Advocard [28]

Answer:

Subtraction

Step-by-step explanation:

Subtraction

153 - 45 = g + 45 - 45

108 = g

3 0
3 years ago
Find the quotient. 5/6 divided by 1/6
Montano1993 [528]

Answer:

5

6

÷  

1

6

=  

5

6

×  

6

1

=  

5 × 6

6 × 1

=  

30

6

=  

30 ÷ 6

6 ÷ 6

=  5

the awnser would be 5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the area of the triangle formed by the origin and the points of intersection of parabolas y=− 1/3 (x−1)^2+8 and y=x^2−2x−3.
Kobotan [32]

Answer:

The area of the triangle formed by origin, and the points (4,5) and (-2,5) will be 15 sq. units.

Step-by-step explanation:

The two parabolas are y = - \frac{1}{3}(x - 1)^{2} + 8 and y = x² - 2x - 3.

Now, solving those two equations we will get the points of intersection.

So, - \frac{1}{3}(x - 1)^{2} + 8 = x^{2} - 2x - 3

⇒ - (x - 1)² + 24 = 3x² - 6x - 9

⇒ -x² + 2x - 1 + 24 = 3x² - 6x - 9

⇒ 4x² - 8x - 32 = 0

⇒ x² - 2x - 8 = 0

⇒ x² - 4x + 2x - 8 = 0

⇒ (x - 4)(x + 2) = 0

So, x = 4 or - 2.

Now, for x = 4 , y = 4² - 2(4) - 3 = 5 and the point of intersection is (4,5).

Or, for x = - 2, y = (- 2)² - 2(- 2) - 3 = 5 and the point of intersection is (-2,5).

Now, points (4,5) and (-2,5) make a straight line parallel to the x-axis at a perpendicular distance of 5 units from origin and its length is (4 - (- 2)) = 6 units.

So, the area of the triangle formed by origin, and the points (4,5) and (-2,5) will be = 0.5 × 5 × 6 = 15 sq. units. (Answer)

8 0
3 years ago
Which statements are true? All parallelograms are rhombuses. All rectangles are squares. All rectangles are parallelograms. All
Simora [160]

Answer:

A.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Which expression is equivalent to
Tasya [4]

Answer:

1/x^24

Step-by-step explanation:

(x^-6/x^2)^3 multiply the powers inside the parenthesis by power outside of the parenthesis to get rid of parenthesis

x^-6×3/x^2×3 = x^-18/x^6

subtract the denominator's power from nominator's power

x^-18-6 = x^-24 ➡ 1/x^24

3 0
3 years ago
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