Ask question

Ask question

All categories

3 years ago

7

The ages of four sisters are consecutive even integers. Two times the age of the youngest sister exceeds the oldest sister's age

by 30 years. The equation 2x − (x + 6) = 30 models the age, x, of the youngest sister. What is the age of the oldest sister?

1 answer:

sasho [114]3 years ago

7 0

Alright, lets get started.

The ages of all four sisters will be = x, x+2, x+4, x+6

As per given in question, two times of youngest sister age exceeds the oldest sister age by 30 means

$2x - 30 = (x+6)$

Simplifying the equation

$2x - (x+6) = 30$

$2x - x - 6 = 30$

$x = 36$

So this is the age of youngest sister.

So, age of oldest sister will be $x + 6 = 36 + 6 = 42$

Hene the age of oldest sister is 42 years. : Answer

Hope it will help :)

You might be interested in

If a 24 pack of cans is 2 for $9 what is the ratio of the number of cans to price

Salsk061 [2.6K]

2:9 should be the answer

5 0

3 years ago

Read 2 more answers

FIND THE VALUE OF X

Crazy boy [7]

Answer:

By using the rule that the interior angles of any triangle equal 180 we see that:

m<ABC+m<CAB+m<ACB=180°

Therefore,

(2x+15)+(x+10)+(3x+5) = 180°

Now we have an equation and can solve for x:

Combine like terms:

(2x+15)+(x+10)+(3x+5) = 180°

6x+30=180°

6x+30-30=180-30

6x=150

x=25

To check our work just plug in 25 for x in each equation and the sum of those answers should add up to 180:

2x+15

2(25)+15

65

x+10

25+10

35

3x+5

3(25)+5

75+5

80

65+35+80=180

x=25 is valid

Step-by-step explanation:

7 0

3 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

3 years ago

PLEASE HELP The areas of two similar triangles are 50 dm2, and 32 dm2. The sum of their perimeters is 117 dm. What is the perime

Novosadov [1.4K]

Answer:

65 dm and 52 dm

Step-by-step explanation:

If the scale factor of the sides is k, then the scale factor of the areas is k^2.

The scale factor of the areas is (32 dm^2)/(50 dm^2) = 0.64 = k^2

The scale factor of the sides is k = \sqrt(0.64) = 0.8

The perimeters are in a ratio of 1:0.8

x + 0.8x = 117

1.8x = 117

x = 65

0.8x = 0.8(65) = 52

The perimeters are 65 dm and 52 dm.

4 0

3 years ago

A square pyramid is sliced in half, parallel to the base.

DIA [1.3K]

Answer:

I think the answer is a because it not getting any smaller

7 0

3 years ago

Read 2 more answers