Answer:
c. break the N2 triple bond.
Explanation:
In the general nitrogen reduction reaction (which occurs in the nitrogenase complex), ferredoxin acts as an electron donor to Fe-protein, which in turn hydrolyzes ATP and reduces MoFe-protein. By reducing MoFe-protein one can then reduce numerous (triple bonded) substrates although, under natural conditions, it reacts only to N2 and H +.
That is, ATP must be present in the reaction so that MoFe-protein can break the triple bond N2.
The binding and hydrolysis of ATP to Fe-protein causes a change in conformation of this protein which facilitates redox reactions. The enzymatic reduction of N2 by nitrogenase requires a large energy investment, although the exact changes in free energy are still unknown.
Answer:
Explanation:
In cellular biology, active transport is the movement of molecules across a membrane from a region of lower concentration to a region of higher concentration—against the concentration gradient. Active transport requires cellular energy to achieve this movement.
The correct answer is upwelling from equatorial to Polar Regions results in bringing oxygen from the epipelagic zone to deeper oceanic zones.
It is a process in which the wind mediated motion of nutrient-rich, dense, and cooler water is moved towards the surface substituting the nutrient depleted and warmer surface water. The epipelagic zone refers to the upper layer of the ocean, which is abundant in oxygen and gets the majority of the sunlight for the procedure of photosynthesis. The upwelling of water from the equatorial to the polar region brings oxygen.
Answer: Telophase
Explanation:
Mitosis is a process of division of the nucleus, which consists of the equal sharing of genetic material (DNA). This type of division occurs in somatic cells and the next step after mitosis is the division of the cytoplasm (cytokinesis), to form two genetically identical daughter cells.
First, it is necessary for the genetic material to be duplicated, so that each newly created cell receives the correct number of chromosomes (structure smade up of DNA). To separate these chromosomes, during <u>anaphase</u>, the chromosomes are anchored to the spindle microtubules and aligned at the metaphase plate (the center of the cell). The sister chromatids (two copies of a chromosome) are separated by the microtubules anchored to their kinetochores as they disassemble, heading toward the respective centrosomes (an organelle in which microtubules grow). Then, the microtubules pushing the centrosomes (and the set of chromosomes associated with them) toward opposite ends of the cell. Since it is necessary for the chromosomes to go to the poles of the cell, new cells are formed. So in this step, <u>it is necessary that the nuclear envelope is not present (otherwise, the nucleus could not divide).</u>
During <u>telophase</u>, microtubules not attached to kinetochores continue to elongate, further stretching the cell. The sister chromosomes are each associated with one of the poles, and as <u>the division of the nucleus is completed, the nuclear envelope reforms around both chromosome sets</u>,<u> using fragments of the nuclear envelope of the original cell.</u> The chromosomes are decondensed back into chromatin and only the cytokineses remain.
The fluorophore labels proteins that are part of the nuclear membrane and as telophase forms back, these proteins are expressed more. So, since the proteins of the nuclear envolope are labeled with a green fluoroforum, the green fluorescence would be most intense during telophase. Therefore there will be more intensity of green color compared to anaphase where the nuclear membrane is disintegrated.
