<span>it all looks confusing when we try to juggle with all those numbers in the head. The problem can be solved systematically by constructing a contingency table.
</span>role/gender B G total
speaking...... 4 4 8
<span> silent............ 4 8 12
total............. 8 12 20
</span>Probability of a child having a speaking part is therefore
(4+4)/20=8/20=2/5
a. 2/5
Answer:
6+3-8-7 = 8
1+4+10-8 = 7
3-3+9+1 = 10
10-2+10-8 = 10
2+0+1+2+3 = 8
10-1-2-3+4 = 8
Step-by-step explanation:
i don't know if these are supposed to be easy or not lol but thanks for the points :p
Use ac method
for ax²+bx+c=0 when a≠1
multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b
2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that
2y²+3y+6y+9=0
group
(2y²+3y)+(6y+9)=0
factor
y(2y+3)+3(2y+3)=0
undistribute
(y+3)(2y+3)=0
set to zero
y+3=0
y=-3
2y+3=0
2y=-3
y=-3/2
y=-3 and -3/2
it's factored form is (x+3)(2x+3)
