Answer:
Solution given:
1.
diameter(d)=6mm
base(b)=8mm
height (h)=5mm
Area of figure=area of parallelogram +area of semi circle
- base*height+½π(d/2)²
- 8*5+½*π×(6/2)²
- 40+14.14
- 54.4mm²
- <u>Area</u><u> </u><u>:</u><u>5</u><u>4</u><u>.</u><u>1</u><u>4</u><u>m</u><u>m</u><u>²</u>
2.
for triangle
base[b]=6ft
height(h)=9ft
for square
length[l]=9ft
Area of figure=area of square +area of triangle
- =l²+½*b*h
- =9²+½*6*9
- =81+27
- =108ft²
- <u>Area</u><u>:</u><u> </u><u>1</u><u>0</u><u>8</u><u>f</u><u>t</u><u>²</u>
C= two step equations require all number to be whole number in order to solve.
Here is an example that disproves that:
.5x + 8= 18
<u> -8 -8</u>
<u>.5</u>x = <u>10
</u>.5 .5
x = 20 (.5 is certainly not a whole number but I solved it anyway)
Step-by-step explanation:
hope I understand your qyestion
Equation 1 : R+G=20
Equation 2 : 7R+3G=9
Multiply Equation by 3, it becomes
3R+3G=60 ...... Equation 3
Now Equation 3 minus Equation 2
-4R = 51
R = - 51/4
Sub R into Equation 1, you can find G
Answer:
a) PR = 17 cm, b) QR = 6 cm
Step-by-step explanation:
∠Q=90, so PQ and QR are legs, and PR is hypotenuse.
Pythagorean theorem PQ² + QR² = PR²
a) PQ² + QR² = PR²
8² + 15² = PR²
PR² = 289
PR = 17 cm
b) PQ² + QR² = PR²
8² + QR² = 10²
64 + QR² = 100
QR² = 36
QR = 6 cm