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alisha [4.7K]
3 years ago
14

F(x) = 4x ; find f(-15)

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0

Answer:

f(-15) = -60

Step-by-step explanation:

Plug in -15 for x:

f(x) = 4x; f(-15) = 4(-15)

Multiply. Note that when you multiply one negative and one positive number together, your answer will be negative.

4 * -15 = -60

-60 is your answer.

~

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Step-by-step explanation: x+4-5=y

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Solve the quadratic equation by completing the square. x2 + 6x + 7 = 0
ruslelena [56]
Hello,

x²+2*3x+3²+7-9=0
==>(x+3)²-2=0
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7 0
3 years ago
Pleaseee help!
user100 [1]

Step-by-step explanation:

f(3)=?

f(x)=2x+5

put x=3,

f(3)=2(3)+5=6+5=11

------------

g(2)=?

g(x)=x^2-3

put x=2,

g(2)=2^2-3=4-3=1

-----------------

g(f(-1))=?

g(x)=x^2-3

and f(-1)=2(-1)+5= -2+5=3

so g(f(-1))=3^2-3=9-3=6

----------------

f(g(-1))=?

f(x)=2x+5

g(x)=g(-1)=(-1)^2-3=1-3= -2

f(g(-1))=2(-2)+5= -4+5=1

----------------

g(f(x))=?

g(x)= x^2-3

put x=f(x),

g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25

7 0
3 years ago
2. Write a quadratic function that has -intercepts (- 3, 0) and (4, 0) and passes through the point (5, 8)
Reptile [31]

Answer:

f(x)=x^2-x-12

Step-by-step explanation:

<u>Quadratic Function</u>

Standard Form of Quadratic Function

The standard representation of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

When the zeros of f (x1 and x2) are given, it can be written as:

f(x)=a(x-x1)(x-x2)

Where a is a constant called the leading coefficient.

We are given the two roots of f: x1=-3 and x2=4, thus:

f(x)=a(x+3)(x-4)

We also know that f(5)=8, thus:

f(5)=a(5+3)(5-4)=8

Operating:

a(8)(1)=8

Solving:

a=1

The function is:

f(x)=1(x+3)(x-4)

Operating:

\boxed{f(x)=x^2-x-12}

5 0
3 years ago
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